(18000s/d)(365d/y)(mi/3500s)=1877.14 mi per year
X+5y=12
5y=12-x
y=(12-x)/5
y=12/5-x/5
The intercept is 12/5
The mean of the distribution given is 0.569.
Given some distribution like under:
x p(x)
0 0.650
1 0.216
2 0.087
3 0.026
4 0.014
5 0.009
We have to find the mean of the distribution.
Mean is the sum of numbers divided by the numbers which are taken into consideration. It is also known as average.
Mean=sum/n
To find the mean of distribution we have to find sum of x*p(x)
∑xp(x)=0*0.650+1*0.216+2*0.0087+3*0.026+4*0.014+5*0.009
=0+0.216+0.174+0.078+0.056+0.045
=0.569
Hence the mean of the distribution given in the question is 0.569.
Learn more about mean at brainly.com/question/1136789
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Distribution in the given question is wrong and the right question is as the right distribution is as under:
x p(x)
0 0.650
1 0.216
2 0.087
3 0.026
4 0.014
5 0.009
So,
1st year: 3
2nd year: 4(first year), which is 12
3rd year: 6(first year), which is 18
The sum of the 1st, 2nd, and 3rd years is 3 + 12 + 18 = 33
Now, multiply 33 by the price at which Mr. Jackson sold each computer ($185).
We get $6105. Mr. Jackson's gross profit was $6105.
Answer:
The area is multiplied by 4
Step-by-step explanation:
4x4=16 (area 1)
4(x2)x4(x2)=64 (area 2 (with the measurements doubled)
64/16=4
