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Doss [256]
2 years ago
15

Given that m∠TSU = m∠SUQ, why is RT || UQ?

Mathematics
1 answer:
o-na [289]2 years ago
6 0
The answer to your question is option A
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Can i get an answer for this​
Dimas [21]

Answer:

Isnt it just 75 degrees?

Step-by-step explanation:

The number in the angle.

8 0
3 years ago
How did you find six things in triangle
AVprozaik [17]
Sorry it's a bit messy. but I hope you understand and it will help

7 0
2 years ago
What is the perpendicular line in slope form of the equation (-5,8);y=1/5x-1
denpristay [2]

Answer: Find the negative reciprocal of the slope of the original line and use the slope-intercept form y=mx+b to find the line perpendicular to y=1/5x−1. y=−5x−17



5 0
3 years ago
Read 2 more answers
Do the following measurements form a triangle? True or false <br><br> 24°, 30° , 126°
Aleks04 [339]

Answer:

True

Step-by-step explanation:

The sum of measures of these three angles of any triangle is invariably equal to the straight angle, also expressed as 180 °.

24+30+126=180

6 0
3 years ago
Find the coordinates of the point (x,y,z) on the planez=4x+3y+1 which is closest to the origin.
Nataliya [291]
Given plane &Pi; : f(x,y,z) = 4x+3y-z = -1
Need to find point P on &Pi;  that is closest to the origin O=(0,0,0).

Solution:
First step: check if O is on the plane &Pi; : f(0,0,0)=0 &ne; -1 => O is not on &Pi;
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e. 
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane &Pi; , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane &Pi;
Answer: P(-2/13, -3/26, 1/26) is the point on &Pi; closest to the origin.

8 0
2 years ago
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