Answer:
i cant SEE the image
Step-by-step explanation:
Answer:
29
Step-by-step explanation:
1. plug in -10 for x
-2(-10) + 9
2. multiply -2 x -10 = 20
20 + 9
3. add 20 + 9 = 29
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Answer:
5 for the first and 4x for the second one also plz give heart
Step-by-step explanation:
i just know
So ten tens = 100 so u multiply and u get 40 tens which are 400= 4 hundreds
