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3 years ago

Another representation, in polar coordinates, of the point (3, 5pi/4) is ( ___, pi/4)

Mathematics

2 answers:

yaroslaw [1]3 years ago

7 0

The correct answer is -3. I just took the test :).

VladimirAG [237]3 years ago

3 0

The answer is (-3, pi/4). I just took the quiz

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Nine less than a number is no more than 8 and is no less than 3.

snow_lady [41]

3 is less than or equal to x-9 is less than or equal to.

3<= x-9<=8

<= these mean less than or equal to.
hope I helped you!

3 0

4 years ago

If g(c)=9/5C+32 find g^-1(41)?<br> Does anyone know the answer?

Scilla [17]

C(f)=(5/9)(f-32) I think

7 0

3 years ago

Need help with math problem if do get 5 star

11Alexandr11 [23.1K]

<h3><u>Answer</u><u>:</u></h3>

The point ( 22 , 23 ) lies in Ist quadrant

<h3><u>Explanation</u><u>:</u></h3>

The intersection of x and y axis divides the coordinate plane into 4 sections. These four sections are called quarrants. These quadrants are named as Roman numerals I, II, III and IV quadrant. The start with the top right corner and move in anti clockwise direction .

In a x y plane , both the values of x and y are positive in Ist quadrant

3 0

2 years ago

Suppose the object moving is Dave, who hasamassofmo =66kgatrest. Whatis Daveâs mass at 90% of the speed of light? At 99% of the

nignag [31]

Step-by-step explanation:

Formula that relates the mass of an object at rest and its mass when it is moving at a speed v:

$m=\frac{m_o}{\sqrt{1-\frac{v^2}{c^2}}}$

Where :

m = mass of the oebjct in motion

$m_o$ = mass of the object when at rest

v = velocity of a moving object

c = speed of the light = $3\times 0^8 m/s$

We have :

1) Mass of the Dave = $m_o=66 kg$

Velocity of Dave ,v= 90% of speed of light = 0.90c

Mass of the Dave when moving at 90% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.90c)^2}{c^2}}}$

m = 151.41 kg

Mass of Dave when when moving at 90% of the speed of light is 151.41 kg.

2) Velocity of Dave ,v= 99% of speed of light = 0.99c

Mass of the Dave when moving at 99% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.99c)^2}{c^2}}}$

m = 467.86 kg

Mass of Dave when when moving at 99% of the speed of light is 467.86 kg.

3) Velocity of Dave ,v= 99.9% of speed of light = 0.999c

Mass of the Dave when moving at 99.9% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.999c)^2}{c^2}}}$

m = 1,467.17 kg

Mass of Dave when when moving at 99.9% of the speed of light is 1,467.17 kg.

4) Mass of the Dave = $m_o=66 kg$

Velocity of Dave,v=?

Mass of the Dave when moving at v speed of light: 500

$500 kg=\frac{66 kg}{\sqrt{1-\frac{(v)^2}{(3\times 10^8 m/s)^2}}}$

$v=2.973\times 10^8 m/s$

Dave should be moving at speed of $2.973\times 10^8 m/s$ .

4 0

3 years ago

a 10 ft ladder leans against a wall with its foot braced 3ft. from wall's base how far up the wall does the ladder resach

geniusboy [140]

Ladder makes a right triangle with the wall and ground. The hypotenuse = length of the ladder = 10 ft
Let the height be h
By Pythagorean theorem
10^2 = 3^2 + h^2
h^2 = 10^2 - 3^2 = 100 - 9 = 91
h = sqrt( 91) = 9.54 ft

6 0

3 years ago