Answer:
26
Step-by-step explanation:
→ Utilise Pythagoras theorem
a² + b² = c²
→ Substitute in the values
10² + 24² = c²
→ Simplify
100 + 576 = c²
→ Simplify further
676 = c²
→ Square root both sides to isolate c
26 = c
If 2 + 5i is a zero, then by the complex conjugate root theorem, we must have its conjugate as a zero to have a polynomial containing real coefficients. Therefore, the zeros are -3, 2 + 5i, and 2 - 5i. We have three zeros so this is a degree 3 polynomial (n = 3).
f(x) has the equation
f(x) = (x+3)(x - (2 + 5i))(x - (2 - 5i))
If we expand this polynomial out, we get the simplest standard form
f(x) = x^3-x^2+17x+87
Therefore the answer to this question is f(x) = x^3-x^2+17x+87
We are told that f(1) = -1.5, and that f(n+1) = -2f(n).
Then: f(2) = -2f(1) = -2(-1.5) = +3 (answer)
The resolvent is:
x = (- b +/- root (b2 - 4ac)) / 2a
To apply it we must have a polynomial of the form:
ax2 + bx + c = 0
Where,
One side of the equation is zero.
The polynomial must be only grade 2.
The coefficient a must be different from zero.
Answer:
options: B, C, D are correct
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