Ask question

Ask question

All categories

2 years ago

14

Given a mean of 61.2 and a standard deviation of 21.4, within how many standard deviations of the mean do the values 45,78,62,90

, and 31 fall?
a.0
b.1
c.2
d.3

2 answers:

vovangra [49]2 years ago

7 0

2 standard deviations or c

givi [52]2 years ago

5 0

The answer is C. ^^^

You might be interested in

Your parents gave you a gift card for your favorite coffee shop. The card was worth $50

meriva

Answer:

y=-3x+50

Step-by-step explanation:

y=50-3x ,where x is number of days.

6 0

2 years ago

Use the distributive property to rewrite the expression 3 (2+11)

kolbaska11 [484]

Answer:

3(2+11) = 3x2 + 3x11

Step-by-step explanation:

4 0

2 years ago

It takes 60 minutes for 7 people to paint 5 walls.

ziro4ka [17]

0.7/1 of a wall per person

3 0

2 years ago

Is this happening to anybody else? Why are there ad's to unlock answers it is annoying

kap26 [50]

I don’t have to have ads. When I wasn’t signed up I had to but I logged in and now I don’t have to watch ads.

6 0

2 years ago

Read 2 more answers

Given that log 2 = 0.3010 and log 3 = 0.4771 , how can we find log 6 ?

bearhunter [10]

Answer:

$\sf \log_{10}6=0.7781$

Step-by-step explanation:

<u>Given</u>:

$\sf \log_{10} 2 = 0.3010$

$\sf \log_{10} 3 = 0.4771$

To find log₁₀ 6, first rewrite 6 as 3 · 2:

$\sf \implies \log_{10}6=\log_{10}(3 \cdot 2)$

$\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay$

$\implies \sf \log_{10}(3 \cdot 2)=\log_{10}3+\log_{10}2$

Substituting the given values for log₁₀ 3 and log₁₀ 2:

$\begin{aligned} \sf \implies \log_{10}3+\log_{10}2 & = \sf 0.4771+0.3010\\ & = \sf 0.7781 \end{aligned}$

Therefore:

$\sf \log_{10}6=0.7781$

Learn more about logarithm laws here:

brainly.com/question/27953288

brainly.com/question/27963321

5 0

1 year ago

Read 2 more answers