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Katena32 [7]
3 years ago
13

Find the limit of the function algebraically. limit as x approaches negative nine of quantity x squared minus eighty one divided

by quantity x plus nine.
Mathematics
1 answer:
scoray [572]3 years ago
7 0
Let me express the equation clearly:

lim x→-9  (x²-81)/(x+9)

Initially, we solve this by substituting x=-9 to the equation. 

((-9)²-81)/(-9+9) = 0/0

The term 0/0 is undefined. This means that the solution is not see on the number line because it is imaginary. Other undefined terms are N/0 (where N is any number), 0⁰, 0×∞, ∞-∞, 1^∞ and ∞/∞. One way to solve this is by applying L'Hopitals Rule. This can be done by differentiating the numerator and denominator of the fraction independently. Then, you can already substitute the x=-9.

(2x-0)/(1+0) = 2x = 2(-9) = -18

The other easy way is to substitute x=-8.999 to the original equation. Note that the term x→-9 means that x only approaches to -9. Thus, you substitute a number that is very close to -9. Substituting x=-8.999

((-8.999)²-81)/(-8.999+9) = -18

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Answer:

23

Step-by-step explanation:

The sides of a square are all the same length, so if 3 of them total 48, one of them must be 48/3 = 16.

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3 years ago
Please help me with this
Citrus2011 [14]

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3 years ago
Which special version of the Pythagorean Theorem can you use to find the length of any square's diagonal, d, using only the leng
kodGreya [7K]
The square's diagonal is the triangle's hypotenuse.

the original Pythagorean theorem is  a^{2} +  b^{2} = c^{2}   where a and b are the two sides and c is the hypotenuse.

that means the Pythagorean theorem for this question is:

s^{2} + s^{2} = d^{2}  or 2( s^{2} )= d^{2}
8 0
3 years ago
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Hi.
Keith_Richards [23]

Answer:

Thank you so much made my day!

Step-by-step explanation:

5 0
3 years ago
Evaluate the expression. Enter your answer in the box. 2³ =
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2^3 = 2 x 2 x 2 = 8

your answer is 8

hope this helps
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