7*6*x^-8*x^3
42x^-8+3 (bases same powers add)
42x^-5
1/42x^5
<span>so the simplified </span>form<span> of 7x^-8*6x^3 is=1/42x^5</span>
Start by decomposing the number inside the root into primes
Then group the terms into cubes if possible

rewrite the root
![\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B80%7D%3D%5Csqrt%5B3%5D%7B10%5Ccdot2%5E3%7D)
then cancel the terms that are cubes and bring them out of the root
Answer: P(not shaded sector) = 0.50
Step-by-step explanation:
Since we have given that
Number of shaded parts = 6
Number of unshaded parts = 6
Total parts = 6+6 = 12
So, Probability of getting not shaded sector is given by

Hence, P(not shaded sector) = 0.50
8+(9t+4)
remove ( )
since there's a + in front of the ( ) the value will not change
8+9t+4
combine like terms
9t+12
Hope this helps
Answer:
i believe C
Step-by-step explanation: