Answer:
Atrial flutter is a type of abnormal heart rhythm, or arrhythmia. It occurs when a short circuit in the heart causes the upper chambers (atria) to pump very rapidly. Atrial flutter is important not only because of its symptoms but because it can cause a stroke that may result in permanent disability or death.
The proportion of days for which the process will shut down for both broth x and broth in the distribution are 2.28 days and 3.34 days.
<h3>How to compute the number of days?</h3>
Mean ( u ) =4.9
Standard Deviation ( sd )=0.6
Normal Distribution = Z= (x - u)/SD
a. P(X > 6) = (6-5.2)/0.4
= 0.8/0.4 = 2
= P ( Z >2)
From the standard normal table.
= 0.0228 = 2.28 days
Broth x = 2.28 days
P(x > 6) = (6-4.9)/0.6
= 1.1/0.6 = 1.8333
= P ( Z >1.833)
From the standard normal table
= 0.0334 = 3.34 days
Broth y = 3.34 days.
The recommendation to the manager as to the broth that should be bought is broth x since it requires lesser days
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For generalized anxiety disorder (gad), the pharmacological treatment of choice has been the category of drugs known as benzodiazepines.
<h3>What is Generalized anxiety disorder?</h3>
- Any age can experience a case of generalized anxiety disorder.
- severe, persistent anxiety that makes daily activities difficult.
- The illness shares symptoms with anxiety disorders such as panic disorder and obsessive-compulsive disorder.
- These signs include difficulty concentrating, restlessness, and unceasing worry.
- Counseling and drugs like antidepressants may be used in treatment.
- For instance, you can experience acute worry about your safety or the safety of those close to you, or you might sense that something negative is about to occur.
- You experience severe distress in social, professional, or other aspects of your life as a result of your anxiety, concern, or physical symptoms.
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Answer:tell an adult,go to the hospital but make sure you disinfect the wound if you can
Explanation:
Answer:a. This study involved comparison of two populations. What were the populations?
1) Pregnant women who took the drug.
2)Pregnant women who didn't take the drug.
b. Do you suppose the data were obtained in a survey or experiment?
- Survey
C.Provide a descriptive statistic that could be used to estimate the number of women out of 1000 in this population who have tissue abnormalities.
-out of 1,000 women developed tissue abnormalities
63/3980=.0158
15.8%
D. remember that women whose mothers took the drug were twice as likely to develop tissue abnormalities.)
___ out of 1,000 women developed tissue abnormalities
15.8/2
7.9
e. Medical sudies often use a relatively large sample (in this case 3980). Why?
medical studies often use a relatively large sample (in this case, 3980) because disease occurrences can be rare and difficult to observe when only isolated populations are considered.
