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maw [93]
2 years ago
12

Jeremy has a weekend job as a soccer referee. One weekend, he earns $140 by working 4 games. Another weekend, he earns $210 by w

orking 6 games. If jeremy graphed an equation that would represent his total earnings based on the number of games worked, what would be the slope of the graph?
A. 7
B. 10
C. 35
D. 70​
Mathematics
2 answers:
boyakko [2]2 years ago
8 0
35 is the correct answer. You figure it out by divided the change in y by the change in x. It is the formula for slope.
210-140. = 70 for change in y
6-4 = 2
Then 70/2= 35

Hope this is helpful to you. Have a nice day.
Ilya [14]2 years ago
6 0

Answer:

$140 divided by 4 games = 35$ per games next $210 divided by 6 games = 35 also so the slope is 35 answer c

Step-by-step explanation:

i am good at this type of math

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Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar
oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 18 means that N = 18

9 are carrying nuclear weapons, which means that k = 9

9 are destroyed, which means that n = 9

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X \leq 1) = P(X = 0) + P(X = 1)

In which

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021

P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0
3 years ago
Please help I dont understand
Degger [83]

Answer:

I think it is B

Step-by-step explanation:

mark me brainliest

3 0
2 years ago
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Fed [463]

We have that

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 $12000<$18400  is ok 

<span> The maximum of hours that I can rent </span>a backhoe <span> are 40 hours, since it is the limit of the operator and it do not overcome the total budget </span>

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What property 14•1=14
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Answer:

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Step-by-step explanation:

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