At what rate per cent per annum will $400 yield an interest of $78 in 1 1/2 years?
1 answer:
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My triangle solver says EF ≈ 7.5 ft.
_____
The law of cosines is usually used for this.
EF^2 = DE^2 +DF^2 -2*DE*DF*cos(D)
.. = 6^2 +11^2 -2*6*11*cos(40°)
.. ≈ 55.88
EF ≈ √55.88 ≈ 7.5 . . . ft
_____
The law of cosines is usually used for this.
EF^2 = DE^2 +DF^2 -2*DE*DF*cos(D)
.. = 6^2 +11^2 -2*6*11*cos(40°)
.. ≈ 55.88
EF ≈ √55.88 ≈ 7.5 . . . ft
Answer:
enrollment decreases by 14.34%.
Step-by-step explanation:
Given that number of students enrolled in 2000 = 823
Given that number of students enrolled in 2010 = 705
705 is less than 823 so that means number of students enrollment is decreasing.
Decrease = 823-705 = 118
Percent decrease is given by formula:
which is approx 14.34%.
Hence final answer is that enrollment decreases by 14.34%