Answer:
The correct option is;
D. 6,5
Step-by-step explanation:
TS and TU are midsegments
Segment PR = 18.2
Segment TS = 6.5
Given that TS is the midsegment of PR and PQ, therefore, TS = 1/2×QR
Which gives;
Segment QR = 2×TS = 2 × 6.5 = 13
Segment QR = 13
Given that TU is a midsegment to PQ and QR, we have that QU = UR
Segment QR = QU + UR (segment addition postulate)
Therefore, QR = QU + QU (substitute property of equality)
Which gives;
QR = 2×QU
13 = 2×QU
Segment QU = 13/2 = 6.5
The length of segment QU is 6.5.
Yo idk maybe ask your teacher for help
<u>Answer:</u>
<h2>
ST = 44.54 ft</h2>
<u>Explanation:</u>
given:
∠T=90° , ∠R=39° and TR = 55 ft
ST = 55×tan(39)
ST = 55×0.80..
ST = 44.54 ft
Answer:
hey the answer is 204ft cubed (for some reason it doesn't let me insert the 3 power so i just wrote it as "cubed" if you dont know what that is its ^3)
Step-by-step explanation:
i just did 2*6*17 and got the answer. Mark brainliest and thank? Yeet! have an awesome day! :D
