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Vinil7 [7]
2 years ago
8

A cone has a diameter of 8 units and a height of 8 units. units, and its volume is Its radius is volume of cubic units. If a sph

ere has the same radius as the cylinder, its volume is cubic units. A cylinder with the same height and radius as the cone will have a the volume of the cylinder.​

Mathematics
1 answer:
aev [14]2 years ago
6 0

The above question is not complete because it was not written and arranged properly

Complete Question

1) A cone has a diameter of 8 units and a height of 8 units. Its radius is 4 units, and its volume is ______ cubic units.

2) A cylinder with the same height and radius as the cone will have a volume ______ of cubic units.

3) If a sphere has the same radius as the cylinder, its volume is ______the volume of the cylinder. Answer: 1) Volume of the cone = 134.04cubic units

2)Volume of the cylinder = 402.12cubic units

3) Volume of the sphere= 268.08 cubic units. Hence, if a sphere has the same radius as the cylinder, its volume is 2/3 times the volume of the cylinder.

Step-by-step explanation:

1) A cone has a diameter of 8 units and a height of 8 units. Its radius is 4 units, and its volume is ______ cubic units.

Volume of a cone = 1/3πr²h

h = 8 units

r = 4 units

Volume = 1/3 × π × 4² × 8

134.04cubic units

2) A cylinder with the same height and radius as the cone will have a volume ______ of cubic units.

Volume of a cylinder = πr²h

Height and radius is the same as that of the cones hence,

h = 8 units

r = 4 units

= π × 4² × 8

= 402.12cubic units.

3) If a sphere has the same radius as the cylinder, its volume is ______the volume of the cylinder.

Volume of a Sphere = 4/3πr³

r = radius of the cylinder = 4 units

Volume of a Sphere = 4/3 × π × 4³

= 268.08 cubic units.

From the above question, we are asked to compare the volume of the sphere with the volume of the cylinder

Volume of the sphere : Volume of the cylinder

268.08 cubic units : 402.12 cubic units

268.08/402.12 = 2/3

Therefore, the volume of the sphere is 2/3 times the volume of the cylinder

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Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shap
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Answer:

0.25 feet per minute

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

\dfrac{dV}{dt}=20$ ft^3/min

\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h

Since base diameter = Height of the Cone

Radius of the Cone = h/2

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\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}

Therefore: \dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=20

We want to determine how fast is the height of the pile is increasing when the pile is 10 feet high.

h=10$ feet$\\\\\dfrac{3\pi *10^2}{12}\dfrac{dh}{dt}=20\\25\pi \dfrac{dh}{dt}=20\\ \dfrac{dh}{dt}= \dfrac{20}{25\pi}\\ \dfrac{dh}{dt}=0.25$ feet per minute (to two decimal places.)

When the pile is 10 feet high, the height of the pile is increasing at a rate of 0.25 feet per minute

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Answer:

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Step-by-step explanation:

The given data points are (-6 4) (-4 0) (-3 -2) (-1 -7). Plot these points on a coordinate plane.

From the graph it is clear that the point are in the form of a straight line, so we need to use the linear regression model.

The general linear regression model is

y=ax+b

Using technology we get

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b=-8.9230769231\approx -8.92

Put a=-2.19 and b=-8.92 in  the above equation.

y=-2.19x-8.92

Therefore the linear regression model is y=-2.19x-8.92.

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