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Andreyy89
3 years ago
6

Given right triangle QRS, what is the value of sin(30°)? StartFraction StartRoot 3 EndRoot Over 3 EndFraction One-half StartFrac

tion StartRoot 3 EndRoot Over 2 EndFraction StartFraction 2 Over 1 EndFraction

Mathematics
2 answers:
emmasim [6.3K]3 years ago
8 0

Answer:

B

Step-by-step explanation:

baherus [9]3 years ago
6 0

Answer:

Option 2: \sin(30)=\frac{1}{2}

Step-by-step explanation:

Given:

From the triangle shown below;

A triangle QRS with angle QRS = 90°, ∠QSR = 30°.

Side QR = 5, SQ = 10 and RS = 5√3

Now, we know from trigonometric ratio that,

\sin (A) = \frac{Opposite\ side}{Hypotenuse}

Here, opposite side of angle QSR is QR and Hypotenuse is the side opposite angle QRS which is SQ. Therefore,

\sin(\angle QSR)=\dfrac{QR}{SQ}\\\\\\\sin(30)=\dfrac{5}{10}\\\\\\\sin(30)=\dfrac{5}{2\times 5}=\dfrac{1}{2}

Therefore, the value of sine of 30° is one-half. So, second option is correct.

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Refer to the triangle below. If a = 4 and b = 6, solve for c. show work Also, give the unsimplified radical form answer and then
9966 [12]

Look at the image below where I labeled the sides

To solve this you must use Pythagorean theorem:

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a = 4

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^^^Plug these numbers into the theorem

4^{2} +6^{2} =c^{2}

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^^^Simplified radical

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5 0
3 years ago
Second Time Asking This:
sattari [20]

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2 years ago
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I found the choices that should have been included in this problem.
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3 years ago
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