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Murrr4er [49]
2 years ago
12

What is the total number of different 9-letter arrangements that can

Mathematics
1 answer:
MissTica2 years ago
5 0
F is it67 17 and 9 and 78
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HELP SOLVE THANK YOU!
Lera25 [3.4K]

Answer:

Solution 1: 1+1\sqrt{3}

Solution 2: 1-1\sqrt{3}

Step-by-step explanation:

x^2-2=2x

x^2-2x-2=0

Use quadratic equation.

(-b+-\sqrt{b^2-4ac})/2a

(2+-\sqrt{(-2)^2-4*1*-2})/2

(2+-\sqrt{(4+8}))/2

(2+-\sqrt{12})/2

Solution 1: (2+2\sqrt{3})/2=1+1\sqrt{3}

Solution 2: 1-1\sqrt{3}

4 0
2 years ago
Read 2 more answers
At a new exhibit in the Museum of Science, people are asked to choose between 94 or 220 random draws from a machine. The machine
Tresset [83]

Answer:

0.0869 = 8.69% probability of getting more than 61% green balls.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

The machine is known to have 99 green balls and 78 red balls.

This means that p = \frac{99}{99+78} = 0.5593

Mean and standard deviation:

\mu = p = 0.5593

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.5593*0.4407}{99+78}} = 0.0373

a. Calculate the probability of getting more than 61% green balls.

This is 1 subtracted by the pvalue of Z when X = 0.61. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.61 - 0.5593}{0.0373}

Z = 1.36

Z = 1.36 has a pvalue of 0.9131

1 - 0.9131 = 0.0869

0.0869 = 8.69% probability of getting more than 61% green balls.

8 0
3 years ago
Which symbol correctly compares these fractions? 13 20 ___ 7 10
fomenos
These are fractions? Like 13/20 and 7/10? Is so the symbol would be 13/20 < 7/10 because 7/10 is a higher fraction than 13/20
7 0
4 years ago
Read 2 more answers
Is relation t a function? Is the inverse of relations t a function? Relation t
seraphim [82]
Relation t is a function because it has no repeating x values

the inverse of relation t is when u switch the x and y values.
ex. inverse of (0,-2) is (-2,0).

and yes, the inverse of relation t is also a function because there are no repeating x values.
3 0
3 years ago
Elm Street is straight. Willard's house is at point H between the school at point S and
Vlad1618 [11]

Answer:

7.5 Miles.

Step-by-step explanation:

3 + 4.5 = 7.5 Miles.

4 0
3 years ago
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