7.) Area of a square pyramid is given by A = s^2 + 2sl; where s is the side length of the base and l is the slant height.
Area of given pyramid = 4^2 + (2 x 4 x 7) = 16 + 56 = 72 ft^2
8.) Area of the given pyramid is the area of the hexagonal base plus the area of the six slant triangles.
Area of hexagonal base = (3sqrt(3))/2 x 10^2 = 150 x 1.732 = 259.8
Area of the 6 traingles = 6(1/2 x 10 x 13) = 6 x 65 = 390
Total surface area of the pyramid = 259.8 + 390 = 649.8 ≈ 650 m^2
9.) Using pythagoras rule, the slant height is sqrt(6^2 + 3.5^2) = sqrt(36 + 12.25) = sqrt(48.25) = 6.9 mm
10.) The surface area of a cone is given by πr^2 + πrl
Area = π x 6^2 + π x 6 x 20 = 36π + 120π = 490.1 cm^2
11.) l = sqrt(r^2 + h^2) = sqrt(11^2 + 16^2) = sqrt(121 + 256) = sqrt(377) = 19m
Answer:
-5/2 because there is -5y/2 but we have to take coefficient only so -5/2
Step-by-step explanation:
Pick two points on the line and determine their coordinates
Select one to be (x1, y1) and the other to be (x2, y2)
Finally use the slope intersect equation to calculate the slope:
<em>Formula-</em><em> </em>
<em>y = mx + b </em>
<em></em>
Hope this helps, let me know if you need more information, I'll be glad to help! :)
Perimeter is adding all sides so the answer will be 12(pi) + 46, hope this helps!!