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NemiM [27]
3 years ago
9

How many different positive integers can be represented as a difference of two distinct members of the set {1, 2, 3, 4, 5, 6}?

Mathematics
1 answer:
slega [8]3 years ago
5 0

For the difference to be positive, when both the minuend and the subtrahend are positive, the former must be greater than the latter.

Therefore

minuend = 2 ⇒ subtrahend = 1 ← 1 number

minuend = 3 ⇒ subtrahend = 1,2 ← 2 numbers

minuend = 4 ⇒ subtrahend = 1,2,3 ← 3 numbers

minuend = 5 ⇒ subtrahend = 1,2,3,4 ← 4 numbers

minuend = 6 ⇒ subtrahend = 1,2,3,4,5 ← 5 numbers

1+2+3+4+5=<u>15</u>

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CAN SOMEONE PLEASE HELP ME ASAP PLEASEE ANYBODY LITERALLY ANYONE OUT THERE PLEASE
marin [14]

Answer:

Y1 is parallel to Y2 and L1 to L2.

Step-by-step explanation:

A line is 180°. To find the degree the angles I subtracted 117 and 63 by 180 to find thair respective angles. (Also 117+63 equil 180) meaning that the Y's and L's are parallel to each other.

6 0
2 years ago
How to write 8/15 as a decimal?
Murrr4er [49]

Answer:

0.53

Step-by-step explanation:

Basically just go to your calculator and put in 8 divded by 15

3 0
2 years ago
Solve (26/57)=(849/5x)
Gnesinka [82]
<span>Cross multiply 26*5x = 849 * 57 130 x = 48393 x = 48393 / 130 x = 372.25</span>
4 0
3 years ago
Read 2 more answers
(x-3) (x-4) polynomial
Debora [2.8K]

Answer:

x^{2} -7x +12

Step-by-step explanation:

Using the Foil method

you multiply x times x and get x^{2}

Then you multiply -4 times X and get -4x

Then you multiply -3 times X and get -3x

then you add -4 and -3 together and get -7x

Lastly you multiply -4 and -3 and get 12

And there you have it

x^{2} -7x +12

8 0
3 years ago
When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F
aleksandr82 [10.1K]

Let x be the unknown number. So, three times that number means 3x, and the square of the number is x^2

We have to sum 528 and three times the number, so we have 528+3x

Then, we have to subtract this number from x^2, so we have

x^2-(3x+528)

The result is 120, so the equation is

x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0

This is a quadratic equation, i.e. an equation like ax^2+bx+c=0. These equation can be solved - assuming they have a solution - with the following formula

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

If you plug the values from your equation, you have

x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}

So, the two solutions would be

x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27

x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24

But we know that x is positive, so we only accept the solution x = 27

6 0
3 years ago
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