Molar mass
NH3 = 17 g/mol
N2 = 28 g/mol
4 NH3 + 6 NO = 5 N2 + 6 H2O
4 x 17 g NH3 ------------ 5 x 28 g N2
?? g NH3 --------------- 300 g N2
300 x 4 x 17 / 5 x 28 =
20400 / 140 => 145.71 g of NH3
The formula of chalcopyrite is CuFeS₂.
The molar mass of chalcopyrite - 183.5 g/mol
The mass of Cu in 1 mol of chalcopyrite is - 63.5 g
When 183.5 g of chalcopyrite is mined, the mass of Cu obtained - 63.5 g
So if 63.g of Cu is needed mass of chalcopyrite required - 183.5 g
Then to gain 370 g of pure Cu - mass of chalcopyrite needed -183.5/63.5 x 370
therefore mass of chalcopyrite to be mined - 1069.21 g
Answer:
<h2>3.156 × 10²² atoms</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>3.156 × 10²² atoms</h3>
Hope this helps you
Answer:
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Explanation:
okay?.........................................
