Missing information:
Equilibrium reaction: NH2COONH4(s)⇌2NH3(g)+CO2(g)
Answer:
14.43 atm
Explanation:
The equilibrium occurs when in a reversible reaction, the velocity of the formation of the products is equal to the velocity of the formation of the reactants. When this occurs, the concentration and partial pressures remain constant. To characterize the equilibrium there's the equilibrium constant, which can be based on the concentration (Kc) or based on the gases partial pressure (Kp).
The conversion between them is:
Kp = Kc*(RT)⁻ⁿ
Where n is the variation of the coefficients of the gas substances (reactants - products) so, n = 0 - (2+1) = -3
Kp = Kc*(RT)³
R is the gas constant (0.082 atm.L/mol.K), and T is the temperature ( 240°C = 513 K), so:
Kp = 0.006*(0.082*513)³
Kp = 446.6
The value of Kp is also the ratio between the multiplication of the partial pressures of the products divided by the partial pressure of the reactants, each one elevated by the coefficient of the substance, and only for gas substances, so:
Kp = (pNH3)²*(pCO2)
Doing an equilibrium chart
NH3 CO2
0 0 Intial
+2x x Reacts (stoichiometry is 2:1)
2x x Equilibrium
446.6 = (2x)²*x
4x³ = 446.6
x³ = 111.65
x = ∛111.65
x = 4.81 atm
pNH3 = 2*4.81 = 9.62 atm
pCO2 = 4.81 atm
By Dalton's law, the total pressure of a gas mixture is the sum of the partial pressure of the substances:
P = 9.62 + 4.81 = 14.43 atm
The body's main requirement of iodine is in the thyroid gland. Therefore, iodized salt would have no effect on any cases of Graves' disease as the thyroid gland is already overactive in this disease.
<h3>
Answer:</h3>
0.002 moles
<h3>
Explanation:</h3>
Concept tested: Molarity
We are given;
- Volume of HCl as 20 ml or 0.02 L
- Molarity of HCl solution as 0.10 M
We are required to calculate the number of moles of HCl
What is molarity?
- Molarity is the concentration of a solution in moles per liter
How is it calculated?
- It calculated by dividing number of moles by volume;
- Molarity = Number of moles ÷ Volume
To calculate the number of moles we rearrange the formula;
Moles = Molarity × Volume
In this case;
Moles of HCl = 0.10 M × 0.02 L
= 0.002 moles
Therefore, the number of moles of HCl is 0.002 moles
Answer:
Even-number fatty acids such as palmitate undergoes complete β-oxidation in the liver motochondria to CO₂ because the product, acetyl-CoA can enter the TCA cycle.
Oxidation of odd-number fatty acids such as undecanoic acid yields acetyl-CoA + propionyl-CoA in their last pass. Propionyl-CoA requires additional reactions including carboxylation in order to be able to enter the TCA cycle.
The reaction CO2 + propionyl-CoA ----> methylmalonyl-CoA is catalyzed by propionyl-CoA carboxylase, a biotin-containing enzyme, which is inhibited by avidin. Palmitate oxidation however, does not involve carboxylation.
Explanation:
Even-number fatty acids such as palmitate undergoes complete β-oxidation in the liver motochondria to CO₂ because their oxidation product, acetyl-CoA, can enter the TCA cycle where it is oxidized to CO₂.
Undecanoic acid is an odd-number fatty acid having 11 carbon atoms. Oxidation of odd-number fatty acids such as undecanoic acid yields a five -carbon fatty acyl substrate for their last pass through β-oxidation which is oxidized and cleaved into acetyl-CoA + propionyl-CoA. Propionyl-CoA requires additional reactions including carboxylation in order to be able to enter the TCA cycle. Since oxidation is occuring in a liver extract, CO₂ has to be externally sourced in order for the carboxylation of propionyl-CoA to proceed and thus resulting in comlete oxidation of undecanoic acid.
The reaction CO2 + propionyl-CoA ----> methylmalonyl-CoA is catalyzed by propionyl-CoA carboxylase, a biotin-containing enzyme. The role of biotin is to activate the CO₂ before its tranfer to the propionate moiety. The addition of the protein avidin prevents the complete oxidation of undecanoic acid by binding tightly to biotin, hence inhibiting the activation and transfer of CO₂ to propionate.
Palmitate oxidation however, does not involve carboxylation, hence addition of avidin has no effect on its oxidation.
The correct answers are:
1. Lithium - C) Opaque solid with higher density
2. Lead - B) Malleable, soft, and shiny
3. Florine - D) Highly reactive gas
4. Krypton - A) Nonreactive gas
I hope that helps u!
:)
