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Nutka1998 [239]
2 years ago
7

Which defines the average kinetic energy of a system’s particles?.

Chemistry
2 answers:
fgiga [73]2 years ago
4 0

Answer:

C. Temperature

Explanation:

EDGE 2022

Nookie1986 [14]2 years ago
3 0

Temperature,as the temperature and therefore, kinetic energy,of a gas changes the ,the RMS speed of the gas molecules also changes

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Stock nomenclature nh4no3
dedylja [7]

Answer: Stock nomenclature of NH_4NO_3 is ammonium(I) nitrate

Explanation:

Stock nomenclature is used for chemical nomenclature where the oxidation states of some or all of the elements in a compound are indicated  by Roman numerals in parentheses.

For example:

FeCl_2 which has iron in oxidation state of +2 has stock nomenclature of iron(II) chloride.

FeCl_3 which has iron in oxidation state of +3 has stock nomenclature of iron(III) chloride.

Thus the stock nomenclature of NH_4NO_3 is ammonium(I) nitrate as ammonium has oxidation state of +1.

6 0
3 years ago
The enthalpy of fusion of H2O (s) at its normal melting point is 6.01 kJ/mol. What is the entropy change for freezing 1 mole of
Rom4ik [11]

Answer:

22.01J/Kmol

Explanation:

The parameters given in this question are;

Enthalpy (H) = 6.01 kJ/mol.

Number of moles = 1

Entropy change (S) = ?

The formular relationship between entropy and enthalpy is given as;

ΔS=ΔH/T

Temperature for water at freezing point = 0C + 273 = 273 K (converting to Kelvin)

ΔS = 6.01/273

ΔS = 0.0220kJ/Kmol

ΔS = 0.02201 * 1000 = 22.01J/Kmol

3 0
3 years ago
A certain phospholipid molecule contains two fatty acid chains of eight carbon atoms each having no carbon-carbon double bonds i
larisa [96]

Answer:

Here's what I get  

Explanation:

The fatty acids form ester C-O bonds with the OH groups of glycerol and the phosphoric acid forms phosphate P-O bonds.

The phosphate also forms P-O ester linkages with the OH groups in other alcohols such as choline.

The structure below shows the phospholipid with two saturated C₈ fatty acids and the phosphate group.

5 0
3 years ago
Explain in detail what information can be learn about atoms of different elements by examining the periodic table. For the maxim
pav-90 [236]

Answer:

  • See below this long answer.

Explanation:

These are the main features of the periodic table that you will be able to relate with some property trends of the atoms like size, energy levels, valence electrons, electronegativity, and ionization energy.

<u>A) Features:</u>

1. Elements are arranged in increasing order of atomic number, i.e. number or protons.

2. Since atoms are neutrals, the number of electrons equals the number of protons, and, as result, the elements are arranged in increasing order of number of electrons.

3. The elements are arranged in 18 columns and 7 rows.

4. The rows are named period and correspond to the principal energy level (n): first row corresponds to n = 1, second row corresponds to n = 2, third to n = 3, and so on up to n = 7. The number of elements in each period are:

Period 1, n = 1, 2 elements

Period 2, n = 2, 8 elements

Period 3, n = 3, 8 elements

Period 4, n = 4, 18 elements

Period 5, n = 5, 18 elements

Period 6, n = 6, 32 elements (this includes the 14 lanthanides)

Period 6, n = 7, 32 elements (this includes the 14 lanthanides)

That makes a total of 118 elements.

5. The columns are named groups and they indicate the number of valence electrons

Group 1: 1 valence electron

Group 2: 2 valence electrons

Group 13: 3 valence electrons

Group 14: 4 valence electrons

Group 15: 5 valence electrons

Group 16: 6 valence electrons

Group 17: 7 valence electrons

Group 18: 8 valence electrons

Groups 3 through 12 includ the transition metals and due they have subshells that are not completely filled, their valence electrons vary.

More like a reference than as a rule these are the number of valence electrons for these groups.

Group 3: 3 valence electrons

Group 4: 2-4 valence electrons

Group 5: 2-5 valence electrons

Group 6: 2-6 valence electrons

Group 7: 2-7 valence electrons

Group 8: 2-3 valence electrons

Group 9: 2-3 valence electrons

Group 10: 2-3 valence electrons

Group 11: 1-2 valence electrons

Group 12: 2 valence electrons

<u>B) Property trends</u>

<u>1. Atomic radius (size)</u>

<u />

  • Down a period (from left to right): due to the increase of the positive charge (number of protons) while the main energy level (n) does not change, the electrons in the valence shell feel a stronger atraction to the nucleus causing that the atomic radius decrease from left to right.

  • Down a group (top to bottom): due to the increase of the main energy level, the outermost orbital is bigger and the atoms become bigger. Thus the trend is that the atomic radius increase when you go down a group.

<u>2. First ionization energy</u>

  • Down a period (from left to right): due to the increase of the nuclear charge (such as explained above) the greater attractive force makes that, in general, the first ionization energy increase from left to right.

  • Down a group (top to bottom): due to the increase in the size of the atom, , generally, the energy to remove an electron from the outermost shell, decrease.

<u>3. Electronegativity</u>

<u />

This is the relative ability to atract electrons in a covalent bond. It increases from left to right and from bottom to top: the most electronegative atoms is fluor.

3 0
4 years ago
PLEASE HELP I NEED THIS ANSWERED IN 10 MINS PLEASE
elena-14-01-66 [18.8K]
We are given the equation to use which is:
ΔG = ΔH - TΔS

We are also given that:
ΔG = 173.3 kJ
T = 303 degrees kelvin
ΔH = 180.7 kJ

Substitute with these givens in the above equation to get ΔS as follows:
ΔG = ΔH - TΔS
173.3 = 180.7 - 303ΔS
303ΔS = 180.7 - 173.3 
303ΔS = 7.4
ΔS = 7.4 / 303 = 0.02442 kJ/K which is equivalent to 24.42 J/k

Based on the above calculations, the correct choice is:
D. 24.42 J/K
4 0
3 years ago
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