D. because the size and shape of the slope determines weather the load can be sustained and c is correct too because the shape affects how much you can load and b. is correct as also because if the volume is very large it can affect the rivers load and flow.
Answer:
Keq =1.50108
Explanation:
The given reactionis
C₂H₂(g) +2H₂(g) -------------> C₂H₂(g)
ΔG0 f=ΔG0f n (products) - ΔG0f n (reactants )
= -32.89 kJ/mol - (209.2 kJ/mol+2*0.0 kJ/mol)
= - 242.09kJ/mol
ΔG= -RTlnKeq
ln Keq = -ΔG/RT
=-(- 242.09kJ/mol ) / 2 k cal /mol*298 K
=0.406
Keq =e0.406
Keq =1.50108
The equation relating velocity and wavelength is written below:
v = λf
where λ is the wavelength in m while f is frequency in 1/s.
Let's determine first the frequency from the speed of light:
c = distance/time, where c is the speed of light equal to 3×10⁸ m/s
3×10⁸ m/s = (300 mm)(1 m/1000 mm)/ time
time = 1×10⁻⁹ seconds
Since f = 1/t,
f = 1/1×10⁻⁹ seconds = 10⁹ s⁻¹
Thus,
v = (795×10⁻⁹ m)(10⁹ s⁻¹)
v = 795 m/s
The molar mass of the imaginary compound Z(AX₃)₂ is the sum of the molar mass of Z, A and X.
<h3>How do we calculate molar mass?</h3>
Molar mass of any compound will be calculated by adding the mass of each atoms present in that compound.
Given compound is Z(AX₃)₂, molar mass of the given compound will be calculated as:
Molar mass of Z(AX₃)₂ = Molar mass of Z + molar mass of 2(A) + molar mass of 6(X)
Hence molar mass of Z(AX₃)₂ is the sum of the masses of all atoms.
To know more about molar mass, visit the below link:
brainly.com/question/18983376
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Complete Question
Magnesium sulfate forms a hydrate with the formula 
. What is the maximum amount of water (in grams) that can be removed from 15 ml of toluene by the addition of 200 mg of anhydrous magnesium sulfate? The molar mass of 
is 120.4 g/mol; H20 = 18 g/mol.
Answer:
The value is 
of 
Explanation:
From the question we are told that
The volume of toluene is 
The mass of anhydrous magnesium sulfate is 
The formula of the hydrate is
The molar mass of is 
From the formula given we see that
1 mole of 
wil remove 7 moles of to for the given formula
Hence
120.4 g (1 mole) will remove 7 moles (7 * 18 g = 126 g ) of to for the given formula
Therefore 1 g of x g of
So
![x = \frac{x]126 * 1}{ 120.4 }](https://tex.z-dn.net/?f=x%20%20%3D%20%20%5Cfrac%7Bx%5D126%20%2A%20%201%7D%7B%20120.4%20%7D)
=> 
From our calculation we obtained that
1 g of will remove of
Then
of will remove z g of of
So
=>
=> of
