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Doss [256]
3 years ago
5

What is 2.08 x 10^-3 in standard form

Chemistry
1 answer:
stepladder [879]3 years ago
6 0

Explanation:

0.00208 is the correct standard form

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Help please! I'd appreciate it 
babymother [125]

Answer:

16.56 g

Explanation:

Mass is the production of Volume and Density.

m = V. d = 6 × 2.76 = 16.56 g

6 0
3 years ago
Sodium, atomic number 11, forms an ionic bond with an atom of an unknown element. What is one possible choice for the other elem
djyliett [7]
The Answer is A 
This is because sodium needs to give off one electron to be stable, form these options the only element that needs to take one electron to be stable is fluorine thus A is the answer
3 0
3 years ago
Read 2 more answers
Why are there so many different kind of apples
Mars2501 [29]
There are many different types of apples i dont EXACTLY know why but however there are some eople that can only have a certain type of apple
8 0
3 years ago
CaC2 + 2H2O → C2H2 + Ca(OH)2 If 2.8 moles of CaC2 are consumed in this reaction, how many grams of H2O are needed?
Strike441 [17]

Answer:

Cac2 is a answer please mark me brainliest

8 0
3 years ago
1]
balu736 [363]

Explanation:

Given -

  • An organic compound gives H₂ gas with Na
  • On treatment with alkaline iodine it gives yellow ppt.
  • On oxidation with CrO₃/H⁺ forms an aldehyde (C₂H₄O)

To Find -

  • Name the compound and write the reaction involved

Now,

Let A be the organic compound.

Then,

  1. A + Na → + H₂↑
  2. A + I₂ → CHI₃ (yellow ppt.)
  3. A + CrO₃ + H⁺ → C₂H₄O

Now,

Here we see that compound A reacts with chromic oxide (CrO₃) in the presence of acidic medium gives aldehyde.

  • Functional group of aldehyde = —CHO

And It forms only 2 Carbon aldehyde it means, It is Ethanal (CH₃CHO).

Compound A reacts with chromic oxide (CrO₃) in the presence of acidic medium gives ethanal.

It means,

We know that 1° alcohol on oxidation gives aldehyde.

Here it gives 2 Carbon aldehyde.

It means,

Here 2 Carbon and 1° alcohol is used.

Now,

Its cleared that Compound A is Ethanol.

Reaction Involved -

  1. CH₃CH₂OH + Na → CH₃CH₂O⁻Na⁺ + H₂↑
  2. CH₃CH₂OH + I₂ + OH⁻ → CHI₃↓ + HCOO⁻ + HI + H₂O
  3. CH₃CH₂OH + CrO₃ + H⁺ → CH₃CHO

6 0
3 years ago
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