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masya89 [10]
3 years ago
11

Explain in detail what information can be learn about atoms of different elements by examining the periodic table. For the maxim

um points earned, you should include the visible information on the periodic table as well as trends of the atoms(size, energy levels, valence electrons, etc,)
WILL MARK BRAINLIEST IF I GET AN A!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!‍‍‍
Chemistry
1 answer:
pav-90 [236]3 years ago
3 0

Answer:

  • See below this long answer.

Explanation:

These are the main features of the periodic table that you will be able to relate with some property trends of the atoms like size, energy levels, valence electrons, electronegativity, and ionization energy.

<u>A) Features:</u>

1. Elements are arranged in increasing order of atomic number, i.e. number or protons.

2. Since atoms are neutrals, the number of electrons equals the number of protons, and, as result, the elements are arranged in increasing order of number of electrons.

3. The elements are arranged in 18 columns and 7 rows.

4. The rows are named period and correspond to the principal energy level (n): first row corresponds to n = 1, second row corresponds to n = 2, third to n = 3, and so on up to n = 7. The number of elements in each period are:

Period 1, n = 1, 2 elements

Period 2, n = 2, 8 elements

Period 3, n = 3, 8 elements

Period 4, n = 4, 18 elements

Period 5, n = 5, 18 elements

Period 6, n = 6, 32 elements (this includes the 14 lanthanides)

Period 6, n = 7, 32 elements (this includes the 14 lanthanides)

That makes a total of 118 elements.

5. The columns are named groups and they indicate the number of valence electrons

Group 1: 1 valence electron

Group 2: 2 valence electrons

Group 13: 3 valence electrons

Group 14: 4 valence electrons

Group 15: 5 valence electrons

Group 16: 6 valence electrons

Group 17: 7 valence electrons

Group 18: 8 valence electrons

Groups 3 through 12 includ the transition metals and due they have subshells that are not completely filled, their valence electrons vary.

More like a reference than as a rule these are the number of valence electrons for these groups.

Group 3: 3 valence electrons

Group 4: 2-4 valence electrons

Group 5: 2-5 valence electrons

Group 6: 2-6 valence electrons

Group 7: 2-7 valence electrons

Group 8: 2-3 valence electrons

Group 9: 2-3 valence electrons

Group 10: 2-3 valence electrons

Group 11: 1-2 valence electrons

Group 12: 2 valence electrons

<u>B) Property trends</u>

<u>1. Atomic radius (size)</u>

<u />

  • Down a period (from left to right): due to the increase of the positive charge (number of protons) while the main energy level (n) does not change, the electrons in the valence shell feel a stronger atraction to the nucleus causing that the atomic radius decrease from left to right.

  • Down a group (top to bottom): due to the increase of the main energy level, the outermost orbital is bigger and the atoms become bigger. Thus the trend is that the atomic radius increase when you go down a group.

<u>2. First ionization energy</u>

  • Down a period (from left to right): due to the increase of the nuclear charge (such as explained above) the greater attractive force makes that, in general, the first ionization energy increase from left to right.

  • Down a group (top to bottom): due to the increase in the size of the atom, , generally, the energy to remove an electron from the outermost shell, decrease.

<u>3. Electronegativity</u>

<u />

This is the relative ability to atract electrons in a covalent bond. It increases from left to right and from bottom to top: the most electronegative atoms is fluor.

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A chemistry student is given 700. mL of a clear aqueous solution at 26.° C. He is told an unknown amount of a certain compound
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Answer:

The correct answer is - yes, 4.57 g of solute per 100 ml of solution

Explanation:

The correct answer is yes we can calculate the solubility of X in the water at 22.0°C. The salt will remain after the evaporate from the dissolved and cooled down at 26°C.

Then, the amount of solute dissolved in the 700 ml solution at 26°C is the weighed precipitate: 0.032 kg = 32 g.

Then solublity will be :

32. g solute / 700 ml solution = y / 100 ml solution

⇒ y = 32. g solute × 100 ml solution / 700 ml solution = 4.57 g.

Thus, the answer is 4.57 g of solute per 100 ml of solution.

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Common additives to drinking water include elemental chlorine, chloride ions, and phosphate ions. Recently, reports of elevated
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Check the explanation

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3 years ago
Given the balanced ionic equation representing the reaction in an operating voltaic cell: zn(s) + cu2+(aq) → zn2+(aq) + cu(s) th
soldi70 [24.7K]

Answer: from the Zn anode to the Cu cathode


Justification:


1) The reaction given is: Zn(s) + Cu₂⁺ (aq) -> Zn²⁺ (aq) +Cu(s)


2) From that, you can see the Zn(s) is losing electrons, since it is being oxidized (from 0 to 2⁺), while Cu²⁺, is gaining electrons, since it is being reduced (from 2⁺ to 0).


3) Then, you can already tell that electrons go from Zn to Cu.


4) The plate where oxidation occurs is called anode, and the plate where reduction occus is called cathode.


So you get that the electrons flow from the anode (Zn) to the cathode (Cu).


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Copper was the first metal to be produced from its ore because it is the easiest to smelt, that is, to refine by heating in the
Ganezh [65]

Answer:

57.48%

Explanation:

Calculate the mass of 1 mole of malachite:

MM Cu = 63.55

MM O = 16.00

MM H = 1.01

MM C = 12.01

(Cu_{2}(OH)_{2}CO_{3})

A mole of malachite has:

2 moles of Cu

5 moles of O

2 moles of H

1 mole of C

MW Malachite = 2*MM(CU) + 5*MM(O) + 2*MM(H) + 1 *MM(C)

MW Malachite = 2*63.55 + 5*16.00 + 2*1.01 + 1*12.01

MW Malachite = 221.13

Mass of Cu in a mole of Malachite = 2*MM(CU) = 127.1

Now divide the mass of Cu by the mass of Malachite

%Cu = \frac{127.1}{221.13} =0.5748=57.48%

7 0
3 years ago
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