Answer:
-1
i do not remember how to solve this but i just answered a question that had this problem in it on my algebra test and that is the right answer
Answer:
question 1 = x7 and question 2 = 24x^3+56x^2 I'm pretty sure
Hello,
5355 is divisble by 3 since 5+3+5+5=18 is divisible by 3
5355=3*1785
1785 is divisble by 3 since 1+7+8+5=21 is divisible by 3
1785=3*595
595 is not divisible by 3 but by 5
595=5*119
119 is divisible by 7 since 1*2+1*3+9*1=14 is divisible by 7.
119=7*17
17 is prime
Answer A
Answer:
First number=22
Second number=28
Step-by-step explanation:
Since you don't know either of the numbers we can call the first number x. The second number is the first number plus 6 or x+6. The sum is 22 more than the larger number so x+6+22 or x+28. Using this we can create the equation x+x+6=x+28. In order to isolate x we would subract x from both sides ending up with x+6=28. Then subract 6 from both sides to get x=22. This means the first number equals 22. Then to solve for the second number you plug 22 in for x to get the equation 22+6= the second number, so the second number is equal to 28. Look below for just the equation.
x+x+6=x+6+22
2x+6=x+28
-x -x
x+6=28
-6. -6
x=22
22+6
=28
22+28= 28+22
50=50
The average of p, q, and r is 40. The average of a, b, c, and d is 5. What is the average of a, b, c, d, p, q, and r?
Pachacha [2.7K]
Answer:
20
Step-by-step explanation:
Average = sum of numbers divided by number of numbers
sum of p q and r: 40*3=120
sum of a b c and d: 5*4=20
sum of a b c d p q r: 120+20=140
average of a b c d p q r: 140/7, or 20
