The diameter of the circular foundation would be 18.8 feet, and the circumference would be 59.1 feet.
If you need the geometry and trigonometry I'll post those. Instead I found an answer at this link: http://jwilson.coe.uga.edu/EMAT6450/Class%20Projects/Scarpelli/Scarpelli_MathematicsBaseballActivity.....
The distance from home plate to the pitcher's mound is 60.5 feet and from home plate to second base is <span>127.28 feet.
Pitcher's Mound to 2nd base = </span><span>
<span>
<span>
66.78</span> </span>f</span>eet
Given those distances, we KNOW a 50 foot sprinkler will NOT reach home plate and second base from the pitcher's mound.
I didn't figure out the pitcher's mound to 1st or to 3rd, since the question is already answered.
The surface area is 47.1 sq in.
Step-by-step explanation:
Given,
The height (h) of the coin (cylinder shaped) = 5 inches
The radius (r) = 1.5 inches
To find the surface area of the coin.
We need to find the lateral surface area of the coin.
Formula
The surface area of the coin of radius r and height h is 2πrh.
Now,
Putting the value of h and r and π=3.14 we get,
Area = 2×3.14×1.5×5 sq inches
= 47.1 sq in
Hence, the surface area is 47.1 sq in.
Answer:
-8
Step-by-step explanation:
let the other number be x
according to the question equation is
-12x = 96
x = 96/-12
x = -8
Answer:
(0,5)
x,y
Step-by-step explanation:
