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Lyrx [107]
2 years ago
13

Consider an ideal intrinsic semiconductor in thermal equilibrium. No external forces or fields are applied to this semiconductor.

At temperatures above 0 K, the electron concentration in the conduction band is non-zero because
A: some electrons from dopant atoms will overcome the bandgap by gained thermal energy.
B: some electrons from dopant atoms will overcome the ionization energy by gained thermal energy.
C: some electrons from the conduction band will overcome the bandgap by gained thermal energy.
D: some electrons from the valence band will overcome the bandgap by gained thermal energy.
Physics
1 answer:
marissa [1.9K]2 years ago
5 0

At temperatures above 0 K, the electron concentration in the conduction band is non-zero because some electrons from the valence band will overcome the bandgap by gained thermal energy. The correct option is D.

<h3>What are electrons?</h3>

The electrons are the spinning objects around the nucleus of the atom of the element in an orbit.

Consider an ideal intrinsic semiconductor in thermal equilibrium. No external forces or fields are applied to this semiconductor.  At temperatures above 0 K, the electron concentration in the conduction band is non-zero because some electrons from the valence band will overcome the bandgap by gained thermal energy.

The semiconductors are free from impurities. At room temperature. Some electrons ion valence band gains energy and cross the bandgap. They get transferred to the conduction band.

Thus, the correct option is D.

Learn more about electrons.

brainly.com/question/1255220

#SPJ1

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How much work is done by the force that moves the charge?
mina [271]

Answer:

The work done by the force is 6μJ

Explanation:

Suppose, A 30 nC charge is moved from a point where V₁ = 130 V to a point where V₂ = -70 V.

We need to calculate the work done by the force

Using formula of work done

W=-q\Delta V

Where, q = charge

\Delta V =potential difference

Put the value into the formula

W=-30\times10^{-9}\times(-70-130)

W=0.000006\ J

W=6\times10^{-6}\ J

W=6\ \mu J

Hence, The work done by the force is 6μJ.

6 0
4 years ago
Suppose you have two meter sticks, one made of steel and one made of invar (an alloy of iron and nickel), which are the same len
Mekhanik [1.2K]

Answer:

  • The difference in length for steel is 2.46 x 10⁻⁴ m
  • The difference in length for invar is 1.845 x 10⁻⁵ m

Explanation:

Given;

original length of steel, L₁ = 1.00 m

original length of invar, L₁ = 1.00 m

coefficients of volume expansion for steel, \gamma_{st.} =  3.6 × 10⁻⁵ /°C

coefficients of volume expansion for invar, \gamma_{in.} =  2.7 × 10⁻⁶ /°C

temperature rise in both meter stick, θ = 20.5°C

Difference in length, can be calculated as:

L₂ = L₁ (1 + αθ)

L₂  = L₁ + L₁αθ

L₂  - L₁ = L₁αθ

ΔL = L₁αθ

Where;

ΔL is difference in length

α is linear expansivity = \frac{\gamma}{3}

Difference in length, for steel at 20.5°C:

ΔL =  L₁αθ

Given;

L₁ = 1.00 m

θ = 20.5°C

\alpha = \frac{\gamma}{3} = \frac{3.6*10^{-5}}{3} = 1.2*10^{-5} /^oC

ΔL  = 1 x 1.2 x 10⁻⁵ x 20.5 = 2.46 x 10⁻⁴ m

Difference in length, for invar at 20.5°C:

ΔL =  L₁αθ

Given;

L₁ = 1.00 m

θ = 20.5°C

\alpha = \frac{\gamma}{3} = \frac{2.7*10^{-6}}{3} = 0.9*10^{-6}/^oC

ΔL  = 1 x 0.9 x 10⁻⁶ x 20.5 = 1.845 x 10⁻⁵ m

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When compounds form, what is one result for the atoms that bonded?
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