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Art [367]
3 years ago
14

Converting compound units

Physics
1 answer:
Blababa [14]3 years ago
4 0

Answer:

Dividing the silicon density by 1000 and then multiply it by 1000000.

Explanation:

A kilogram equals 1000 grams and a cubic meter equals 1000000 cubic centimeters. Hence, we must divide the silicon density by 1000 and then multiply itby 1000000 to convert the value into kilograms per cubic centimeter. That is:

x = 2.33\,\frac{g}{cm^{3}}\times \frac{1\,kg}{1000\,g}\times \frac{1000000\,cm^{3}}{1\,m^{3}}

x = 2330\,\frac{kg}{m^{3}}

In a nutshell, we must multiply the density of silicon by 1000 to obtains its value in kilograms per cubic meter.

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State Pascal's principle of transmission of pressure​
bulgar [2K]

Answer:

Pascal's law (also Pascal's principle or the principle of transmission of fluid-pressure) is a principle in fluid mechanics given by Blaise Pascal that states that a pressure change at any point in a confined incompressible fluid is transmitted throughout the fluid such that the same change occurs everywhere.

4 0
3 years ago
Why is specific heat important
Ad libitum [116K]
Hey!!

here is your answer >>>

Specific heat is the amount of heat required to raise the temperature of a unit substance!. The most common example!. The specific heat of water is 1 !. And, lot of plays and animals live under the water and if the specific heat of the water would be low, then the aquatic organisms would die, but the specific heat is high and it is hard for the sun to increase the temperature!.

Hope my answer helps!
3 0
3 years ago
If a person walks 1km north , 5 km West , 3km south and 7km east, find the resultant displacement vector
raketka [301]

Y = +1-3 = -2  

X = -5+7 = +2  

D = √2^2-2^2 = 2√1+1 = 2√2 km

3 0
3 years ago
A. How many calories are needed to raise the temperature of 1 gram of water by 1 °C?
sweet-ann [11.9K]

A) 1 cal

B) 80 cal

C) 540 cal

Explanation:

A)

The amount of heat energy needed to raise the temperature of a certain mass of a substance is given by

Q=mC\Delta T

where

m is the mass of the substance

C is the specific heat capacity

\Delta T is the change in temperature

In this problem:

m = 1 g is the mass of water

C=1 cal/g^{\circ}C is  the specific heat capacity of water

\Delta T=1^{\circ}C is the change in temperature

So, the heat needed is

Q=(1)(1)(1)=1 cal

B)

For a solid substance at its melting point, the amount of heat needed to melt completely the substance is given by

Q=m\lambda_f

where

m is the mass of the substance

\lambda_f is the specific latent heat of fusion of the substance

In this problem:

- The ice is already at melting point, 0 °C

- Mass of the ice: m=1g

- Specific latent heat of fusion of ice: \lambda_f=80 cal/g

So, the heat needed is

Q=(1)(80)=80 cal

C)

For a liquid substance at its boiling point, the amount of heat needed to boil completely the substance is given by

Q=m\lambda_v

where

m is the mass of the substance

\lambda_v is the specific latent heat of vaporization of the substance

In this problem:

- The water is already at boiling point, 100 °C

- Mass of the water: m=1g

- Specific latent heat of vaporization of water: \lambda_v=540 cal/g

So, the heat needed is

Q=(1)(540)=540 cal

5 0
3 years ago
What is approximate resistance between P and Q?<br> a) 0.5<br> b)0.8<br> c)2.0<br> d)2.2<br> e)3.6
Rufina [12.5K]

Answer:

0.5 Ohms

Explanation:

We note that the node Q is also between the resistors of 1ohm and 2ohms.

We note that the node P is also between the resistors of 2ohms and 3ohms.

Thus, all these resistors are in parallel, beween nodes P and Q

1/Re=1/R1+1/R2+1/R3

1/Re=1/1+1/2+1/3=(6+3+2)/6=11/6 [ohm^(-1)]

Re=6/11=0.54ohms

Rounding to the tenth: Re=0.5 ohms

8 0
3 years ago
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