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aleksandr82 [10.1K]
2 years ago
11

If the factors of quadratic function g are (x − 7) and (x + 3), what are the zeros of function g?

Mathematics
1 answer:
MArishka [77]2 years ago
8 0

Answer: B. -3 and 7

Step-by-step explanation:

To find the zeros, just move the constants to the other side,

x - 7 ⇒ x = 7

x + 3 ⇒ x = -3

If the number is moved to the other side its sign becomes opposite

Hope it helps!

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How many times does the quadratic function intesect the x axis y=2x^+7x+6
atroni [7]

Answer:

There are two intersections

Step-by-step explanation:

The number of intersections can be found by calculating the delta of the equation

Δ=b²-4ac

if Δ=0, there is 1 intersection

if Δ>0 there are 2 intersections

if Δ=<0, there are no intersections

where the quadratic equation is in the form ax²+bx+c

Δ=7²-4(2)(6)

=1>0

There are two intersections

6 0
3 years ago
The size of a playground is 160 feet by 360 feet. A model is created that measures 4 inches by 9 inches. Is it a rate, ratio onl
Vera_Pavlovna [14]

Answer:

The model is made in a<u> 1:40 ratio </u>

Step-by-step explanation:

How many times is 4 multiplied to be equal to 160?

4(x) = 160

X = 160 / 4

<u>X = 40</u>

The proportion, rate, and ratio are almost the same.

They represent the correspondence between the parts and the whole since they all express a binary relationship between the quantities, that is, objects, people, tablespoons.

If the ratio is 1: 2 it could be read that for every 1 there are 2.

For example 1: 2 cups; For every cup of something there are 2 cups of something else.

In this case, 1:40; For every inch of the model, there are 40 feet in the playground.

3 0
3 years ago
Harry has a penny collection with 160 pennies. He plans to increase the size of his collection by a constant term each year for
mel-nik [20]

Answer:

  • A: Harry plans to have approximately 350 pennies at the end of the second year

  • B: Harry plans to have approximately 1,200 pennies at the end of his five-year plan.

  • C: Harry plans to increase his collection by approximately 1,050 pennies over the five-year period.

  • D: Harry will add approximately 250 pennies to his collenction d during the fourth year, according to his plan.

  • E: The coordinates of the point are (3.5, 400)

  • F: Harry will need to add approximately 150 more pennies more than what he had planned by the end of the fourth year, to get back on the plan.

Explanation:

The first thing I did was to write the numbers to the grid and add the points labeled with the letter of the question with which they are related.

  • Every mark on the x-axis corresponds to 1 year.

  • Every mark of the y-axis corresponds to 200 pennies.

See the graph attached.

Question A:

The y-coordinate of the green point labeled A is about half way between 300 and 400, i.e. 350.

Then, Harry plans to have approximately 350 pennies at the end of the second year

Question B:

The green point labeled B has coordinates (5, 1200), meaning that Harry plans to have approximately 1,200 pennies at the end of his five-year plan.

Question C:

Harry started his collection with approximately 150 coins. It is the y-coordinate (the value when x = 0): (200 - 100)/2 = 150.

Thus, Harry plans to increase his collection by approximately 1,200 - 150 = 1,050 pennies over the five-year period.

Question D:

The number of peenies that Harry will add to his collection during the fourth year, according to his plan, is the difference between the number of pennies at the end of the fourth year and the end of the third year.

The green point labeled D has coordinates (4, 800) meaning that his plan is to have approximately 800 pennies.

To find the number of pennies that Harry plans to have at the end of the third year  read the y-coordinate that meets the curve when x = 3. That is approximately (600 + 500) / 2 = 550.

The difference is 800 - 550 = 250 pennies.

Therefore, Harry will add approximately 250 pennies to his collenction d during the fourth year, according to his plan.

Question E:

The blue point labeled E shows the position on the grid of the 400 pennies halfway throuhg the fourth year.

The coordinates of this point is (3.5, 400).

Question F:

According to the plan, the number of pennies at the end of the fourth year would be 800 (green point labeled D on the graph).

Then, Harry will need to add approximately 800 - 400 = 400 pennies.

According to the plan the number of coins at the end of the third year would be

But the plan was to add 800 - 550 = 250.

Thus, Harry will need to add 400 - 250 = 150 more pennies than he had planned, during the fourth year.

7 0
3 years ago
Read 2 more answers
Your grandfather gave you $1.65 with
Lelu [443]

Answer:

$1.98

Step-by-step explanation:

1.65/5=0.33

1.65+0.33=1.98

check: 1.98/6 =0.33

0.33x5=1.65

5 0
3 years ago
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which of the fallowing functions has a slope 3/2 and contains the midpoint segment between (6, 3) and (-2, 11)?
kolbaska11 [484]
Well, we know the slope is 3/2, what's the midpoint of those anyway?

\bf \textit{middle point of 2 points }\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ 6}}\quad ,&{{ 3}})\quad &#10;%  (c,d)&#10;&({{ -2}}\quad ,&{{ 11}})&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{-2+6}{2}~~,~~\cfrac{11+3}{2} \right)\implies (2,7)

so, what's the equation of a line whose slope is 3/2 and runs through 2,7?

\bf \begin{array}{lllll}&#10;&x_1&y_1\\&#10;%   (a,b)&#10;&({{ 2}}\quad ,&{{ 7}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{3}{2}&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-7=\cfrac{3}{2}(x-2)&#10;\\\\\\&#10;y-7=\cfrac{3}{2}x-3\implies y=\cfrac{3}{2}x+4
4 0
3 years ago
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