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2 years ago

If the factors of quadratic function g are (x − 7) and (x + 3), what are the zeros of function g?

Mathematics

1 answer:

MArishka [77]2 years ago

8 0

Answer: B. -3 and 7

Step-by-step explanation:

To find the zeros, just move the constants to the other side,

x - 7 ⇒ x = 7

x + 3 ⇒ x = -3

If the number is moved to the other side its sign becomes opposite

Hope it helps!

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PLEASE HELP ASAP !!!

BartSMP [9]

You know that a straight line has an angle of 180 degrees;

48+x+x=180 <-- since they are all on the same time
48+2x=180
2x=180-48
2x=132
x=132/2
x=66

Therefore, the x value is 66 degree.

Hope I helped :)

8 0

3 years ago

Which statement is true?

Veronika [31]

Answer:

B. Only 140 is an outlier

Step-by-step explanation:

To properly identify an outlier, you must first know what it is. An outlier is a number that is either a lot higher or a lot lower than the average in a set of numbers. For example, if you had a number set of 1, 3, 4, 6, and 72, you can deduce that 72 is the outlier because it's very far away compared to the other numbers in the set.

In the set that's provided, the numbers tend to range in the double digits, going up in small increments from 15 to 89. However, we can see that 140 is a lot higher than the rest of the numbers in the set, so we can assume that 140 is an outlier.

7 0

3 years ago

Read 2 more answers

Matthew invested $3,000 into two accounts. One account paid 3% interest and the other paid 8% interest. He earned 4% interest on

boyakko [2]

Answer:

Mathew invested $600 and $2400 in each account.

Solution:

From question, the total amount invested by Mathew is $3000. Let p = $3000.

Mathew has invested the total amount $3000 in two accounts. Let us consider the amount invested in first account as ‘P’

So, the amount invested in second account = 3000 – P

Step 1:

Given that Mathew has paid 3% interest in first account .Let us calculate the simple interest $(I_1)$ earned in first account for one year,

$\text {simple interest}=\frac{\text {pnr}}{100}$

Where

p = amount invested in first account

n = number of years

r = rate of interest

hence, by using above equation we get $(I_1)$ as,

$I_{1}=\frac{P \times 1 \times 3}{100}$ ----- eqn 1

Step 2:

Mathew has paid 8% interest in second account. Let us calculate the simple interest $(I_2)$ earned in second account,

$I_{2} = \frac{(3000-P) \times 1 \times 8}{100} \text { ------ eqn } 2$

Step 3:

Mathew has earned 4% interest on total investment of $3000. Let us calculate the total simple interest (I)

$I = \frac{3000 \times 1 \times 4}{100} ----- eqn 3$

Step 4:

Total simple interest = simple interest on first account + simple interest on second account.

Hence we get,

$I = I_1+ I_2 ---- eqn 4$

By substituting eqn 1 , 2, 3 in eqn 4

$\frac{3000 \times 1 \times 4}{100} = \frac{P \times 1 \times 3}{100} + \frac{(3000-P) \times 1 \times 8}{100}$

$\frac{12000}{100} = \frac{3 P}{100} + \frac{(24000-8 P)}{100}$

12000=3P + 24000 - 8P

5P = 12000

P = 2400

Thus, the value of the variable ‘P’ is 2400

Hence, the amount invested in first account = p = 2400

The amount invested in second account = 3000 – p = 3000 – 2400 = 600

Hence, Mathew invested $600 and $2400 in each account.

3 0

3 years ago

Read 2 more answers

A bag contains six red and ten black marbles if you pick a marble from the bag what is the probability that the marble will be b

dimulka [17.4K]

Answer:

125

Step-by-step explanation:

The total number of marbles is 6+10 = 16

P (black) = black / total

= 10/16 = 5/8

With 200 draws, take the probability of P(black) times 200 since the marble is returned each time

200 * (5/8) = 125

We would expect to get 125 black marbles

6 0

3 years ago

6h − (9−3h) = 6 − 3 (h+2) h=3/2 h=3/4 h=17/6 h=7/2

Andre45 [30]

I would try going with h =7/2 if that is wrong just rate me 1

3 0

3 years ago