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aleksandr82 [10.1K]
2 years ago
11

If the factors of quadratic function g are (x − 7) and (x + 3), what are the zeros of function g?

Mathematics
1 answer:
MArishka [77]2 years ago
8 0

Answer: B. -3 and 7

Step-by-step explanation:

To find the zeros, just move the constants to the other side,

x - 7 ⇒ x = 7

x + 3 ⇒ x = -3

If the number is moved to the other side its sign becomes opposite

Hope it helps!

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Help me for 10 points!!
attashe74 [19]
-2y + 2

Explanation

We have (x - y + 1) - (x + y - 1)

Let’s expand the Parentheses

= x - y + 1 - x - y + 1

Then let’s group the like terms

= (x - x) + (- y - y) + (1 + 1)

= 0 - 2y + 2

= 2y + 2
6 0
3 years ago
(Hypothetical.) Suppose five measurements of the volume of a liquid yield the following data (in milliliters).
ElenaW [278]

Answer:

(48.106 ; 53.494)

Step-by-step explanation:

Given the data:

X : 52 48 49 52 53

Sample mean = ΣX / n

n = 5

Sample mean, xbar = 254 / 5 = 50.8

Standard deviation, s = 2.17 (using calculator)

The standard error (SE) : s/√n =2.17/√5 = 0.970

The degree of freedom, df = n-1

df = 5 - 1 = 4

Tscore(0.05, 4) = 2.776

Confidence interval :

Xbar ± Tscore*standard error

50.8 ± (2.776 * 0.970)

50.8 ± 2.694

Lower boundary = 50.8 - 2.694 = 48.106

Upper boundary = 50.8 + 2.694 = 53.494

(48.106 ; 53.494)

7 0
3 years ago
What is the value of e ^(in 7x) A,1 B,7e C,7x D,7
ElenaW [278]

I will have to assume that you actually meant  " e^(ln 7x).  The exponential and logarithmic functions are inverses of each other, so d^(ln 7x) = 7x (answer C).

7 0
3 years ago
Select the correct answer.
oee [108]

Answer:

a² + b² = c²

Step-by-step explanation:

Pythagorean theorem: a² + b² = c²

3 0
3 years ago
Choose ALL possible answers
muminat
Select all the correct answers:
1) Yes

2) No
x=8→h(8)=2(8)^2+5(8)+2=2(64)+40+2=128+40+2→h(8)=170
x=8→f(8)=3^8+2=6,561+2→f(8)=5,563>170=h(8)

3) Yes

4) No

5) Yes
rg=[g(3)-g(2)]/(3-2)=[g(3)-g(2)]/1→rg=g(3)-g(2)
g(3)=20(3)+4=60+4→g(3)=64
g(2)=20(2)+4=40+4→g(2)=44
rg=64-44→rg=20

rf=f(3)-f(2)
f(3)=3^3+2=27+2→f(3)=29
f(2)=3^2+2=9+2→f(2)=11
rf=29-11→rf=18

rh=h(3)-h(2)
h(3)=2(3)^2+5(3)+2=2(9)+15+2=18+15+2→h(3)=35
h(2)=2(2)^2+5(2)+2=2(4)+10+2=8+10+2→h(2)=20
rh=35-20→rh=15

rg=20>18=rf
rg=20>15=rh

6)  No
x=4→g(4)=20(4)+4=80+4→g(4)=84
x=4→h(4)=2(4)^2+5(4)+2=2(16)+20+2=32+20+2→h(4)=54
x=4→f(4)=3^4+2=81+2→f(4)=83>54=h(4)
f(4)=83<84=g(4)
7 0
3 years ago
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