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Nookie1986 [14]
2 years ago
14

I need help with this i need to find the grey area

Mathematics
2 answers:
Soloha48 [4]2 years ago
7 0

Answer:

y < 4x - 2

Step-by-step explanation:

Determine the equation of the line:

  • Choose two points on the line: (1, 2) and (0, -2)
  • Calculate the slope
    Slope  = change in y ÷ change in x = (-2 -2) ÷ (0 - 1) = -4 ÷ -1 = 4
    Therefore, y = 4x + b (where b is the y-intercept)
  • From inspection, y-intercept = -2
  • So equation of the line: y = 4x - 2

A solid line means the signs ≤ or ≥ should be used (inclusive boundary)

A dotted line means the signs < or > should be used (non inclusive boundary).

> is points above the boundary line

< is points below the boundary line

Therefore, the grey shaded area is y < 4x - 2

IrinaVladis [17]2 years ago
6 0

Answer:

y < 4x - 2

Step-by-step explanation:

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Which of the following illustrates a phase shift?
Natasha_Volkova [10]

<u>Answer:</u>

A. y = -2 - cos(x-π)


<u>Explanation:</u>

<u>The general form of the trig equation is:</u>

y = A sin (Bx + C) + D

where:

A is the amplitude

\frac{2\pi}{B} is the period

\frac{-C}{B} is the phase shift

D is the vertical shift


<u>Now, let's check the choices:</u>

<u>A. y = -2 - cos(x-π)</u>

\frac{-C}{B} = \frac{\pi}{1}  = \pi

Therefore, the function has a phase shift of π


<u>B. y = 3 cos(4x)</u>

\frac{-C}{B} = \frac{0}{4} = 0

Therefore, the function has no phase shift


<u>C. y = tan(2x)</u>

\frac{-C}{B} = \frac{0}{2} = 0

Therefore, the function has no phase shift


<u>D. y = 1 + sin(x)</u>

\frac{-C}{B} = \frac{0}{1} = 0

Therefore, the function has no phase shift


<u>Based on the above,</u> the correct answer is A


Hope this helps :)

3 0
3 years ago
Read 2 more answers
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