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Nookie1986 [14]

2 years ago

14

I need help with this i need to find the grey area

2 answers:

Soloha48 [4]2 years ago

7 0

Answer:

y < 4x - 2

Step-by-step explanation:

Determine the equation of the line:

Choose two points on the line: (1, 2) and (0, -2)
Calculate the slope
Slope = change in y ÷ change in x = (-2 -2) ÷ (0 - 1) = -4 ÷ -1 = 4
Therefore, y = 4x + b (where b is the y-intercept)
From inspection, y-intercept = -2
So equation of the line: y = 4x - 2

A solid line means the signs ≤ or ≥ should be used (inclusive boundary)

A dotted line means the signs < or > should be used (non inclusive boundary).

> is points above the boundary line

< is points below the boundary line

Therefore, the grey shaded area is y < 4x - 2

IrinaVladis [17]2 years ago

6 0

Answer:

y < 4x - 2

Step-by-step explanation:

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Which of the following illustrates a phase shift?

Natasha_Volkova [10]

<u>Answer:</u>

A. y = -2 - cos(x-π)

<u>Explanation:</u>

<u>The general form of the trig equation is:</u>

y = A sin (Bx + C) + D

where:

A is the amplitude

$\frac{2\pi}{B}$ is the period

$\frac{-C}{B}$ is the phase shift

D is the vertical shift

<u>Now, let's check the choices:</u>

<u>A. y = -2 - cos(x-π)</u>

$\frac{-C}{B} = \frac{\pi}{1} = \pi$

Therefore, the function has a phase shift of π

<u>B. y = 3 cos(4x)</u>

$\frac{-C}{B} = \frac{0}{4} = 0$

Therefore, the function has no phase shift

<u>C. y = tan(2x)</u>

$\frac{-C}{B} = \frac{0}{2} = 0$

Therefore, the function has no phase shift

<u>D. y = 1 + sin(x)</u>

$\frac{-C}{B} = \frac{0}{1} = 0$

Therefore, the function has no phase shift

<u>Based on the above,</u> the correct answer is A

Hope this helps :)

3 0

3 years ago

Read 2 more answers