Question

Procaine hydrochloride (MW = 273) is a 2-ion electrolyte, dissociating 80%. Calculate its dissociation factor. Round to tenths place.

Answer 1

Answer:

Dissociation factor = 1.8

Explanation:

Data provided in the question:

Molecular weight of the Procaine hydrochloride = 273

Number of ions contained, n = 2

Fraction Dissociating, α = 80% = 0.8

Now,

the  dissociation factor 'i' is given as:

i = 1 + α × ( n - 1 )

on substituting the respective values, we get

i = 1 + 0.8 × ( 2 - 1 )

or

i = 1 + ( 0.8 × 1 )

or

i = 1.8