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3 years ago

7 - 7(-8 + x) = -14 + 4x How do you solve for x

2 answers:

7 0

First thing you need to do is distributive property and that will give you
7-56-7x=-14+4x then combine like terms which will then give you
-49-7x=-14+4x Next get your letters on the left do that by subtracting 4x which will give you -49-11x=-14. After that you will add 49 to both sides which will give you
-11x= 35. Divide by -11 to get x=3.18

QveST [7]3 years ago

5 0

Use distributive property first. Then combine like terms. Subtract the 4x from both sides. Then divide whatever you got and you get whatever x is. Hope it makes sense

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DUE TOMARROW PLEAEE HELP

FrozenT [24]

Answer:

-3/5

Step-by-step explanation:

10-8/4-12=-0.6=-3/5

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3 years ago

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3 years ago

The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are

almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = the number that are not correctly calibrated.

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_3$

So, the required probability = $\frac{^{6}C_3}{^{8}C_3}$

= $\frac{20}{56}$ = 0.35

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_2$

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_1$

So, the required probability = $\frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}$

= $\frac{30}{56}$ = 0.54

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_1$

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_2$

So, the required probability = $\frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}$

= $\frac{6}{56}$ = 0.11

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0

3 years ago

Calculate the value of 4x2 + xy when x = 3 and y=-2.

Alchen [17]

Answer:

Step-by-step explanation:

4x squared + xy

4x(4x) + xy

12(12) + 3 x 2

144 + 6

= 150

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3 years ago

Evaluate 15 ÷ 3 • (-2) + |-10| 0 15/2 -20

Crazy boy [7]

5 * -2 + 10
-10 + 10
The answer is 0

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3 years ago