Answer:
The factors of given expression are 10+10√2 and 10-10√2.
Step-by-step explanation:
We have given a quadratic expression.
s²-20s-100
We have to find factors of given expression.
We use quadratic formula to find factors.
x = (-b±√b²-4ac) / 2a
From given expression, a = 1 , b = -20 and c = -100
Putting values in above formula, we have
x = (-(-20)±√(-20)²-4(1)(-100) ) / 2(1)
x = (20±√400+400 ) / 2
x = (20±√800) / 2
x = (20± √400×2) / 2
x = (20±20√2) / 2
x = 10±10√2
Hence, the factors of given expression are 10+10√2 and 10-10√2.
The denominator 13 cannot be factored so that only 2's and 5's show up, so this means that 2/13 is a non-terminating decimal. Therefore, this decimal repeats itself
Use a calculator to see that: 2/13 = 0.153846 153846 153846 ....
The spaces are put in to help make the number more readable. Note how the "153846" keeps repeating forever
I'll solve it algebraically
x+y=4
x-3y=12
multiply first equatoin by -1 and add to second
-x-y=-4
<u>x-3y=12 +</u>
0x-4y=8
-4y=8
divide both sides by -4
y=-2
sub back
x+y=4
x+-2=4
add 2 to both sides
x=6
x=6
y=-2
(6,-2)
