The average speed, in km/minute, of the train is 2.79 km/minute
<h3>Calculating average speed </h3>
From the question, we are to calculate the average speed in km/minute
From the given information,
Distance travelled = 503 km
Time taken = 3 hours = 3 × 60 minutes = 180 minutes
Using the average speed formula,
Average speed = Distance / Time
∴ Average speed of the train = 503 / 180
Average speed of the train = 2.79 km/minute
Hence, the average speed, in km/minute, of the train is 2.79 km/minute
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Answer:
Try solving 6(n-5)-2.
Step-by-step explanation:
I believe this can be set up as 6(n-5)-2. The difference of a number and five can be represented by n-5. If this needs to be multiplied by 6 (hence 6 times), it would become 6(n-5). Two less than that is represented by -2. Thus, two less than six times the difference of a number and five is 6(n-5) -2, which, when n=9 is plugged in, looks like 6(9-5) -2. Follow PEMDAS from there.
Answer:
csc θ = 13/12
Step-by-step explanation:
cos θ = 12/13
Formula: cos θ = 1/cscθ
Its just the reciprocal.
solve:
1/csc θ = 12/13
csc θ = 13/12
1.3 million stocks was there in beginning of the day
Answer:
2^3 x 3 x 5^2
Step-by-step explanation:
600/2
300/2
150/2
75/3
25/5
5/5
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