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kirill115 [55]
1 year ago
15

Discuss what you view as one of your personal math strengths (e.g. easily adding numbers in your head, quickly understanding dat

a on graphs/charts, savvy at saving or budgeting money, etc).
Mathematics
1 answer:
JulijaS [17]1 year ago
7 0

My view on  my person strengths in maths is that i am good at

  • Mathematical Reasoning
  • Deductive Reasoning
  • Number Facility
<h3>What is my strength in maths?</h3>

My strength in maths can be find in the area of:

Mathematical Reasoning- This is known to be the ability of a person to be able to  make a choice on the right mathematical methods or formulas to use in handling a problem.

In terms if Number Facility, I known that I can be able to add, subtract, multiply, and also divide quickly and rightly.

In terms of Deductive Reasoning, I know that I can be able to use the general rules to an given problems to get answers that are correct.

Therefore, My view on  my person strengths in maths is that i am good at

  • Mathematical Reasoning
  • Deductive Reasoning
  • Number Facility

Learn more about deductive Reasoning from

brainly.com/question/860494

#SPJ1

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What number in 328 is in the tenths place
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2

Step-by-step explanation:i believe hope it helps:)

6 0
3 years ago
Round 47.6001 to the nearest thousandth_______.
irakobra [83]
47.60<u>0</u>1
         ^thousandth place

the answer is  47.600 or 47.6
5 0
3 years ago
If five numbers are selected at random from the set {1,2,3,...,20}, what is the probability that their minimum is larger than 5?
Zanzabum

Answer:

the probability that their minimum is larger than 5 is 0.2373

Step-by-step explanation:

For calculate the probability we need to make a división between the total ways to selected the 5 numbers and the ways to select the five numbers in which every number is larger than 5.

So the number of possibilities to select 5 numbers from 20 is:

<u>20                </u> * <u>      20         </u>*  <u>        20     </u> *<u>        20         </u>* <u>       20 </u>

First number  2nd number   3rd number  4th number   5th number

Taking into account that a number can be chosen more than once, and the order in which you select the numbers matters, for every position we have 20 options so, there are  20^{5} ways to select 5 numbers.

Then the number of possibilities in which their minimum number is larger than 5 is calculate as:

<u>15                </u> * <u>      15         </u>*  <u>           15     </u> *<u>        15          </u>* <u>       15 </u>

First number  2nd number   3rd number  4th number   5th number

This time for every option we can choose number from 6 to 20, so we have 15 numbers for every option and the total ways that satisfy the condition are  15^{5}

So the probability P can be calculate as:

P=\frac{15^{5} }{20^{5} } \\P=0.2373

Then the probability that their minimum is larger than 5 is 0.2373

7 0
3 years ago
In 2008 a house is worth $350 000.
julsineya [31]

Answer:

The value of 2008 is 112% of the Value of 2007.

But we need 100% of the year of 2007.

So 350000/112=3125=>1%

3125*100=312500=>100%

The answer is $312500

3 0
3 years ago
Read 2 more answers
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