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Gre4nikov [31]
2 years ago
10

In cyber security, one of the best ways to protect a computer or network is with a strategy called defense in depth. This strate

gy means that there are multiple defenses put in place. If one fails, it is likely another will catch the problem. Which method of reducing complexity is this concept most closely aligned with
Computers and Technology
2 answers:
emmainna [20.7K]2 years ago
5 0

This idea is most closely related to the Layering in terms of how to reduce complexity.

<h3>Describe cybersecurity?</h3>

The term "cybersecurity" refers to the safeguarding of computer systems and networks against the leakage, theft, or destruction of data as well as the interruption of the services they offer.

Defense in depth is a technique used in cybersecurity that is one of the greatest ways to safeguard a computer or network. If one fails, it's likely that another will identify the issue. The approach to simplifying that is most in line with is called layering.

Thus, This idea is most closely related to the Layering in terms

For further details about cybersecurity, click here:

brainly.com/question/13016321

#SPJ1

galina1969 [7]2 years ago
3 0

The method of reducing complexity is this concept most closely aligned with the Layering.

<h3>What is cyber security?</h3>

Cyber security refers to the protection of computer systems and networks from information disclosure, theft, or damage as well as the disruption of the services they provide.

In cyber security, one of the best ways to protect a computer or network is with a strategy called defense in depth. If one fails, it is likely another that will catch the problem. Layering refers to the method of reducing complexity that is most closely aligned with.

Learn more about cyber security here:

brainly.com/question/17175779

#SPJ1

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Given the following adjacency matrix, what is the approximate rank vector after one iteration of the power iteration method (use
ValentinkaMS [17]

Note: The matrix referred to in the question is: M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]

Answer:

a) [5/18, 5/18, 4/9]'

Explanation:

The adjacency matrix is  M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]

To start the power iteration, let us start with an initial non zero approximation,

X_o = \left[\begin{array}{ccc}1\\1\\1\end{array}\right]

To get the rank vector for the first Iteration:

X_1 = MX_0

X_1 =  \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]\left[\begin{array}{ccc}1\\1\\1\end{array}\right] \\\\X_1 = \left[\begin{array}{ccc}5/6\\5/6\\4/3\end{array}\right]\\

Multiplying the above matrix by 1/3

X_1 = \left[\begin{array}{ccc}5/18\\5/18\\4/9\end{array}\right]

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