Answer:
Written in Python
name = input("Name: ")
wageHours = int(input("Hours: "))
regPay = float(input("Wages: "))
if wageHours >= 60:
->total = (wageHours - 60) * 2 * regPay + 20 * 1.5 * regPay + regPay * 40
else:
->total = wageHours * regPay
print(name)
print(wageHours)
print(regPay)
print(total)
Explanation:
The program is self-explanatory.
However,
On line 4, the program checks if wageHours is greater than 60.
If yes, the corresponding wage is calculated.
On line 6, if workHours is not up to 60, the total wages is calculated by multiplying workHours by regPay, since there's no provision for how to calculate total wages for hours less than 60
The required details is printed afterwards
Note that -> represents indentation
Note: The matrix referred to in the question is: ![M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]](https://tex.z-dn.net/?f=M%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2F2%261%2F3%260%5C%5C1%2F2%261%2F3%260%5C%5C0%261%2F3%261%5Cend%7Barray%7D%5Cright%5D)
Answer:
a) [5/18, 5/18, 4/9]'
Explanation:
The adjacency matrix is
To start the power iteration, let us start with an initial non zero approximation,
![X_o = \left[\begin{array}{ccc}1\\1\\1\end{array}\right]](https://tex.z-dn.net/?f=X_o%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C1%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
To get the rank vector for the first Iteration:
![X_1 = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]\left[\begin{array}{ccc}1\\1\\1\end{array}\right] \\\\X_1 = \left[\begin{array}{ccc}5/6\\5/6\\4/3\end{array}\right]\\](https://tex.z-dn.net/?f=X_1%20%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2F2%261%2F3%260%5C%5C1%2F2%261%2F3%260%5C%5C0%261%2F3%261%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C1%5C%5C1%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5CX_1%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%2F6%5C%5C5%2F6%5C%5C4%2F3%5Cend%7Barray%7D%5Cright%5D%5C%5C)
Multiplying the above matrix by 1/3
![X_1 = \left[\begin{array}{ccc}5/18\\5/18\\4/9\end{array}\right]](https://tex.z-dn.net/?f=X_1%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%2F18%5C%5C5%2F18%5C%5C4%2F9%5Cend%7Barray%7D%5Cright%5D)
Complete Question:
Write statements that output variable numComputers as follows. End with a newline. There are 10 computers.
#include <iostream>
using namespace std;
int main()
{
int numComputers;
cin >> numComputers; // Program will be tested with values: 10.
...
return 0;
}
Answer:
cout << "There are ";
cout << numComputers;
cout << " computers." << "\n";
Explanation:
Using three cout statements the string "There are 10 computers." is printed out, notice that the variable numComputers is entered by the user when the program is run. Another way of concatenating an integer variable and string for printout is by the use of the + (plus) operator.
Using the python code we can say that it will be possible to calculate the neutrons and organize them as:
<h3>The code can be written as:</h3>
<em>def get_total_derivative(self,l_id):</em>
<em>def sigmoid(x, div = 0):</em>
<em>if div == 1: </em>
<em>return np.exp(-x) / (1. + np.exp(-x))**2.</em>
<em>if div == 2: </em>
<em>return - np.exp(x) * (np.exp(x) - 1) / (1. + np.exp(x))**3.</em>
<em>return 1. / (1. + np.exp(-x)) </em>
<em />
<em>def linear(x, div = 0):</em>
<em>if div == 1: </em>
<em>return np.full(x.shape,1)</em>
<em>if div > 2: </em>
<em>return np.zeros(x.shape)</em>
<em>return x </em>
<em />
<em />
<em />
See more about python at brainly.com/question/18502436
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