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3 years ago

Which ordered pair is a solution of the equation y equals x minus 3

1 answer:

6 0

Y = x-3

Basically you just need to plug in an x value and solve for y
y = x - 3
y = (4) - 3
y = 1

In this case, the ordered pair of this equation would be (4, 1)

You can do this given any x or y coordinate

Hope this helps

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Two angels of triangle measure 12 and 40 what is the measure of the third angle of the triangle

yawa3891 [41]

Answer:

128

Step-by-step explanation:

all angles of a triangle will always equal 180

so, we know 2 angles

180-40

140-1128

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2 years ago

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Explain the steps in finding the midpoint of the points (-1,2) and (3,-6). The state the midpoint

blondinia [14]

Answer:

(1, -2)

Step-by-step explanation:

midpoint x = (x₁ + x₂) / 2

midpoint y = (y₁ + y₂) / 2

$(\frac{-1 + 3}{2} , \frac{2 + -(6)}{2} )$

= (1, -2)

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3 years ago

Change from scientific notation to expanded form 8.63 × 10^5

natka813 [3]

The answer will be 863000. Hope it help!

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3 years ago

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38- Blank:_____=12c+4+3c

dimaraw [331]

Answer:

38-15c-4

Step-by-step explanation:

38-x=12c+4+3c

38-x=15c+4

x=38-15c-4

7 0

2 years ago

Determine the equation of the circle graphed below. ( please help me )

Brums [2.3K]

Answer:

$Equation : \\(x+3)^2 + ( y -2)^2 = 36$

Step-by-step explanation:

For standard form the circle's equation we need the centre of the circle and the radius.

Step 1: Find the centre

If the centre is not given find the end points of the diameter

and then find the mid point.

Let the end points of the diameter be : ( - 3 , 8 ) and ( -3 , -4 )

The mid-point of the diameter is :

$Mid-point = (\frac{-3 + - 3}{2}, \frac{-4+8}{2}) = (-3, 2)$

Therefore, centre of the circle = ( -3 , 2 )

Step 2 : Find radius

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the end points ( -3 , 8) and ( -3 , -4 )

That is ,

$Diameter = \sqrt{(-3-(-3))^2 + ( -4 -8)^2}\\$

$= \sqrt{(-3 + 3)^2 + (-12)^2}\\\\=\sqrt{0 + 144}\\\\=12$

Therefore ,

$Radius = \frac{12}{2} = 6$

Step 3 : Equation of the circle

Standard equation of the circle with centre ( h ,k )

and radius ,r is :

$(x - h)^2+(y -k)^2 = r^2$

Therefore, the equation of the circle with centre ( -3, 2)

and radius = 6 is :

$(x - (-3))^2 + (y - 2)^2 = 6^2\\\\(x + 3)^2 + (y - 2)^2 = 36$

5 0

2 years ago