Show me the full question
Answer:
34,220
Step-by-step explanation:
Because order doesn't matter, but the numbers can't be repeated, we need to find the number of combinations where 3 individual numbers can be chosen out of 60 possible numbers using the binomial coefficient:

Thus, Elias can make 34,220 unique 3-number codes given 60 different numbers.
The answer would be C (17/6)
This is because;
6 goes into 17 twice leaving a reminder of 5.
5 and three tenths translates to 5.3 and 2 and five tenths translates to 2.5... 5.3 - 2.5 = 2.8
2.8 translates to 2 and 8 tenths which can be simplified to...
2 and 4 fifths
Well 43 ones times 3 tens is basically 43 times 30 which is 1,290
then divide that by ten to get how many tens and you will get 129 tens
hope this helps