Answer: I think the answer would be 270 miles in 6 hours or 45mph.
S
Answer:
n = 15
Step-by-step explanation:
For inputs of the value of n, the running time for the algorithm A is 100n^2 and that of B is 2^n.
If A is to run faster than B, 100n^2 must be smaller than 2^n.
Let's check from n = 1 to know the value of n that fits
n = 1
100(1)^2 > 2^1
100 > 2
n = 2
100(2)^2 > 2^2
400 > 4
n = 4
100(4)^2 > 2^4
1600 > 16
n = 8
100(8)^2 > 2^8
6400 > 2^8
n = 16
100(16)^2 < 2^16
25600 < 2^16
This implies that between n = 8 and 16, A starts to run faster than B
n = (8+16)/2 = 12
100(12)^2 > 2^12
14400 > 2^12
n = (12+16)/2 = 14
100(14)^2 > 2^14
19600 > 2^14
n = (14+16)/2
n = 15
100(15)^2 < 2^15
22500 < 2^15
At n= 15, A starts running faster than B
Answer:
20.3 units
i’m sorry if wrong, hope this helps!!
5x + 3y = 7> (4) 5x + (4) 3y = (4) 7
4x + 5y = 3> (-5) 4x + (-5) 5y = (-5) 3
20y + 12y = 28
-20x -25y = -15
(X's cross out) 12y - 25y = 28 -15
-13y = 13
Y = -1
(Plug in for y) 5x + 3(-1) = 7
5x -3 =7 (add 3 to 7)
5x = 10 (divide by 5)
X= 2
Ordered Pair= (2, -1)
Answer:
k = 8.4, j = 13.1
Step-by-step explanation:
Solve for k:
Solve for j:
