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Vitek1552 [10]
2 years ago
13

Hey everyone I need some help. Base your answer to the following question on the diagrams below which represents two different c

ells. In both cells, the organelles labeled E are the sites of
A) Secretion
B) Starch Synthesis
C) Food Storage
D) Aerobic Respiration/ Production of ATP

Biology
1 answer:
I am Lyosha [343]2 years ago
5 0

Answer:

aerobics respiration or production of ATP

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Base substitutions in coding regions that result in changed amino acids are called
Cerrena [4.2K]
Missense mutations.

Hope this helps!
7 0
3 years ago
1. How does the number of chromosomes in a cell that results from meiosis compare to the number of chromosomes in the original c
gtnhenbr [62]

Explanation:

2osotsptso5eye is the best way for me for a few years boys to get a new job in a good place to be able and not just be the only component that has to do you appreciate the time you spend with me for the

5 0
2 years ago
Use what you know about natural selection to fill in the blanks in the hypothesis.It should answer the lab question what is the
Vinil7 [7]

Answer:

The correct answer would be -

If the type of food available changes, then the frequency of beak also changes because the beak of the bird suited to food will survive successfully.

Explanation:

According to the theory of natural selection, an organism that is able to adapt according to the change in the environment, it helps in their survival and increases their number in the system.

It is given that the type of food available is changing, so it will lead to the change in the frequency of bird beaks in that particular area. So, if they adapt to survive under the changes in the available food type, otherwise not be able to survive and die.

So,

If the type of food available changes, then the frequency of beak also changes because the beak of the bird suited to food will survive successfully.

5 0
3 years ago
A genetically heterogeneous population of rice has a mean in the number of days to maturation of 30. Selection for decreased per
chubhunter [2.5K]

Answer:

h² = 0.6

Explanation:

Before answering the question, we need to know a few concepts.

<u>Artificial selection</u> is the selecting practice of a specific group of organisms in a population -that carry the traits of interest- to be the parents of the following generations.

Parental individuals carrying phenotypic values of interest are selected from the whole population. These parents interbreed, and a new generation is produced.

<u>The selection differential, SD,</u> is the difference between the mean value of the trait in the population (X₀) and the mean value of the parents, (Xs). So,  

SD = X₀ - Xs

<u>Heritability in the strict sense, h²</u>, is the genetic component measure to which additive genetic variance contributes. The heritability might be used to determine how the population will respond to the selection done, R.  

h² = R/SD

The <u>response to selection (R) </u>refers to the metric value gained from the cross between the selected parents. R can be calculated by multiplying the heritability h², with the selection differential, SD.  

R = h²SD  

R also equals the difference between the new generation phenotypic value (X₁) and the original population phenotypic value (X₀),  

R = X₀ - X₁

-------------------------------------------------------------------------------------------------------------

Now that we know these concepts and how to calculate them, we can solve the proposed problem.

Available data:  

  • You are selecting rice´s decreased period of maturation.
  • The population of rice has a mean maturation time of 30 days → X₀
  • Parental selected average period to maturation is 25 days → Xs
  • F1 plants mature on average in 27 days → X₁
  • N arrow sense Heritability → h²

According to what we sow previously, we need to find out the value of h².

We know that h² = R/SD, so we need to get R and SD first.  

R = X₁ - X₀

R = 27 - 30

R = -3

SD = Xs -  X₀  

SD = 25 - 30

SD = -5

Knowing this, we can calculate h²

h² = R/SD

h² = -3/-5  

h² = 0.6

 

7 0
2 years ago
Can Hippodamia convergens and Hippodamia variegata can mate and produce fertile offspring? Explain your answer.
borishaifa [10]

Hippodamia convergens and Hippodamia variegata can mate but cannot produce fertile offspring because the number of chromosomes can make the development of the embryo unfeasible.

<h3>What are fertile hybrids?</h3>

The crossing between plants or animals of similar species can generate beings that, despite being hybrids, are fertile, even though in the initial phase of cell multiplication some chromosomes do not find the respective pair.

<h3>Why don't hybrids reproduce?</h3>

These differences in the number of chromosomes can make the development of the embryo unfeasible, as the alignment of equivalent chromosomes from the female and the male is necessary for the division of the fertilized cell to occur. When this alignment does not occur, the cell does not reproduce and dies.

With this information, we can conclude that Hybrid animals are beings from genetic crosses between different species, but of the same genus, that is, when two different animals cross and a new animal appears, usually sterile, due to their incompatible genes: the hybrid animal.

Learn more about hybrid animal in brainly.com/question/15362550

#SPJ1

8 0
2 years ago
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