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photoshop1234 [79]
3 years ago
9

Carly is traveling to visit family. She drives x miles on the first day and y miles on the second day for a total of 800 miles.

What are the domain and range of this relationship?
Mathematics
2 answers:
Komok [63]3 years ago
7 0

Answer:

domain: 0 ≤ x ≤ 800

range: 0 ≤ y ≤ 800

Step-by-step explanation:

Dmitrij [34]3 years ago
5 0

Answer:

The domain and range of this relationship is (-∞,∞) and (-∞,∞) respectively.

Step-by-step explanation:

We are given that Carly is traveling to visit family.

She drive distance on first day = x

She drive distance on second day = y

We are also given that Carly is travelling a total of 800 miles.

So,x+y=800

We are supposed to find domain and range of this relationship.

y=800-x

Domain : (-∞,∞)

Range:(-∞,∞)

Hence the domain and range of this relationship is (-∞,∞) and (-∞,∞) respectively.

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PLEASE HELP DUE IN LESS THAN 5 WILL MARK BRAINLIEST!!!!!!!!!!
RUDIKE [14]

Answer:

1. 1:4

2. y = 4 x X

3. yes

Step-by-step explanation:

1. every 1 minuet he cleans 4 shrimp

2. y is the number of shrimp and x is the time. if every miuet he cleans 4 shrimp, then that means you have to multiply the shrimp by the minuets. for example, if he spends 2 minuets, he cleans 8 shrimp because 2 x 4 = 8.

3. This is a proportional relationship because if you were to put this on a graph, it would be a strait line. for example, if you were to plot x (the time) on a line (this line would go horizontal) and y (shrimp) on the line (this line goes verticle) 1 minuet = 4 shrimp. 2 minuets = 8 shrimp. 3 minuets = 12 shrimp. 4 minuets = 16 shrimp.

i hope this helps. tell me if this is too confusing or if you need more help. have a great day :)

6 0
3 years ago
ABC is translated 6 units up and 3 units left to create ∆A'B'C'.
aivan3 [116]
B is the right answer for  this 

6 0
3 years ago
Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear
AlladinOne [14]

Answer:

x=\frac{83}{50}

Step-by-step explanation:

we know that

If the three points are collinear

then

m_A_B=m_A_C

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope AB

we have

A(1,\frac{2}{3}),B(x,-\frac{4}{5})

substitute in the formula

m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}

m_A_B=\frac{\frac{-12-10}{15}}{x-1}

m_A_B=-\frac{22}{15(x-1)}

step 2

Find the slope AC

we have

A(1,\frac{2}{3}),C(-\frac{1}{2},4)

substitute in the formula

m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}

m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}

m_A_C=-\frac{20}{9}

step 3

Equate the slopes

m_A_B=m_A_C

-\frac{22}{15(x-1)}=-\frac{20}{9}

solve for x

15(x-1)20=22(9)

300x-300=198

300x=198+300

300x=498

x=\frac{498}{300}

simplify

x=\frac{83}{50}

8 0
3 years ago
PLZ ANSWER 75 POINTS FAST!!!!!!!!!!!!!!!!
Contact [7]

Answer:

6 inches

Step-by-step explanation:

The volume of a triangular pyramid can be found using

v=1/3bh

where b is the area of the base, and h is the height

We know the volume is 12, so let's find the area of the base

The area of a triangle can be found using:

a=bh/2

We know the base is 4, and the the height is 3, so we can substitute them in

a=4*3/2

a=12/2

a=6

Now, we can solve for the height

v=1/3bh

Substitute 12 in for v, and 6 in for b

12=1/3(6h)

Multiply both sides by 3

3*12=1/3(6h)*3

36=6h

Divide both sides by 6

h=6

The height is 6 inches

5 0
3 years ago
Read 2 more answers
GIVING BRAINILEST-
Nutka1998 [239]

Answer:

To construct a dilation, we need the center of dilation, which is the point from which we make the image smaller or larger. We also need a scale factor, which is the number that determines how large or small we are making the new image. If the scale factor is greater than 1, we have an enlargement, because the new image will be larger than the original image. If the scale factor is less than 1, we have a reduction because the new image will be smaller than the original image.

Enlargement

Step-1

Let's dilate triangle PQR by a scale factor of 2 with a center of dilation at point C.

Step-2

First, we will use a straightedge to connect the center of dilation C to each vertex. We are going to extend those lines across the whole page.

Step-3

Next, we'll place the point of the compass on the center of dilation C and the pencil on vertex Q and measure that distance.

Step-4

Now, without changing the size of the compass, we will move the point of the compass to vertex Q, and make a mark on the line that is extended through Q.

Step-5

Notice that since we measured the distance from C to Q and then used that same distance to mark the line, we have now created a new point that is twice the distance from C that Q was.

We now repeat the process for each of the other vertices of the triangle.

Step-6

These marks represent the vertices of our dilated image. We often use the same letters with an apostrophe to show that it is the corresponding vertex.

Step-7

Finally, we use the straightedge to connect all of the new vertices.

Now,See how triangle P

′

Q

′

R

′

is twice the size of the original triangle.

Reduction

Step-1

Given triangle PQR, now let's dilate the image with a center of dilation at C and with a scale factor of

2

1

Step-2

Using the straightedge, we will connect all of the vertices to the center of dilation C. In this case, since our scale factor is less than 1, we are reducing the size of the triangle.

Step-3

The green lines are the new lines that we have drawn.

Since we have to reduce the size of the triangle by half, we want to cut the distance in half from each vertex to the center of dilation. In order to do this, we will set our compass to a distance that is more than halfway between vertex P and point C but less than the total distance.

Step-4

Keeping the compass at that same distance, start with the point of the compass on vertex P, then draw a curve that intersects the line between P and C. Next, keeping the compass at the same distance, place the point of the compass on C and draw a curve that intersects the line between P and C and intersects the previously drawn curve.

Step-5

Now, we will take the straightedge and connect the points where the curves overlap.

4 0
3 years ago
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