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nlexa [21]
2 years ago
14

B) Wax is a solid at room temperature. Air is a gas. Air's density is 1.30kg/m³

Chemistry
2 answers:
never [62]2 years ago
7 0

The density of wax is <u>much higher</u> than the density of air because they are rigid and denser.

<h3>What is Density? </h3>

<em>Density </em>is defined as the mass of a unit volume of a material substance.

It is given by the formula,

Density = Mass / Volume

The units of density are g/cm³, kg/m³ etc.

Gases are not as dense compared to solids. This is because the particles in <u>solids</u> are very close to each other and the intermolecular gaps are very less. This makes them rigid and dense.

Thus, solids are denser than gases.

Wax is a solid and air is gas.

Hence, the density of wax is <u>much higher</u> than the density of air

Learn more on Density here: brainly.com/question/1897586

#SPJ1

Gwar [14]2 years ago
3 0

The density of wax much higher than the density of air because of its more mass.

<h3>Why is the density of wax much higher than the density of air?</h3>

The density of wax is much higher than the density of air because of its state of matter. We know that wax is a solid substance whereas air is a gaseous substance and we also know that solid substance is heavier than gas so wax has higher density as compared to air.

So we can conclude that the density of wax much higher than the density of air because of its more mass.

Learn more about density here: brainly.com/question/1354972

#SPJ1

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1 electron has charge =1.602* 10⁻¹⁹ C
1 mole of electrons have 1.602* 10⁻¹⁹*6.02*10²³C = 9.64*10⁴ C/1mol

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An equimolar mixture of acetone and ethanol is fed to an evacuated vessel and allowedto come to equilibrium at 65°C and 1.00 atm
frutty [35]

The question is incomplete, the table of the question is given below

Answer:

I) xA= 0.34, yA= 0.55

ii) 76.2 mole % vapor

iii) Percentage of vapor volume = 98%

Explanation:

i) xA= 0.34, yA= 0.55

 xA= 0.34, yA= 0.55

ii)      0.50 = 0.55 nv + 0.34 nL

     Therefore, nV =    0.762 mol vapor and nL = 0.238 mol liquid

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iii)  ρA= 0.791 g/cm3 and,  ρE = 0.789 g/cm3

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So Ml = (0.34 x 58.08)+[(1 -0.34) x 46.07] = 50.15 g/mol

1 mol liquid = (0.762 mol vapor/0.238 mol liquid) = 3.2 mol vapor

Liquid volume = Vl= [1 mol x (50.15 g/mol)] / (0.790 g/cm3) = 63.48 cm3

Vapour volume = Vv = 3.2 mol x(22400 cm3/mol) x [(65+273)/273] = 88747 cm3

Therefore, percentage of vapour volume = 88747 / (88747+63.48) = 99.9 %

3 0
2 years ago
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