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2 years ago

Calculate the theoretical yield of ammonia produced by the reaction of 100g of H2 gas and 200g of N2 gas

1 answer:

6 0

To get the theoretical yield of ammonia NH3:
first, we should have the balanced equation of the reaction:
3H2(g) + N2(g) → 2NH3(g)
Second, we start to convert mass to moles
moles of N2 = N2 mass / N2 molar mass
= 200 / 28 = 7.14 moles
third, we start to compare the molar ratio from the balanced equation between N2 & NH3 we will find that N2: NH3 = 1:2 so when we use every mole of N2 we will get 2 times of that mole of NH3 so,
moles of NH3 = 7.14 * 2 = 14.28 moles
finally, we convert the moles of NH3 to mass again to get the mass of ammonia:
mass of NH3 = no.moles * molar mass of ammonia
= 14.28 * 17 = 242.76 g

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A solution is made by dissolving 23.0 g KOH in 1.60 L H2O. What is the molality of the solution? The density of water is 1.00 g/

artcher [175]

The molarity of a solution is defined as the moles of solute dissolved per kilogram of solvent. Therefore, we first compute the moles of KOH using:

Moles = mass / Mr
Moles = 23 / 56
Moles = 0.41

The volume of solvent is 1.6 liters
The density is 1 gram/cm³ = 1 kg/L
Mass of solvent = density * volume
Mass of solvent = 1 * 1.6
Mass of solvent = 1.6 kg

Molality = moles / kilogram
Molarity = 0.41 / 1.6
Molarity = 0.26

The molality of the solution is 0.26 molal.

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2 years ago

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Which equation shows how wavelength is related to velocity and frequency?

Nataly_w [17]

Answer:

The correct option is the option;

$\lambda = \dfrac{v}{f}$

Explanation:

The wavelength of a wave is the distance between two successive crests of the wave

Therefore, the wavelength, λ, is given by the fraction of the velocity, <em>v</em>, of the wave divided by the frequency, <em>f</em>, (the number of cycles that pass through a point) of the wave

Mathematically, we have;

$The \ wavelength, \ \lambda = \dfrac{The \ wave \ velocity, \ v}{The \ wave \ frequency, \ f}$

$\lambda = \dfrac{v}{f}$

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2 years ago

What current (in a) is required to plate out 1. 22 g of nickel from a solution of ni2 in 0. 50 hour?

Mashcka [7]

The current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.

<h3>What is current?</h3>

The current is given as the product of the charge with time. In the electrochemical analysis of the nickel, there will be a reduction of the nickel ion to nickel. The formation is given as:

$\rm Ni^{2+}+2e^-\;\rightleftharpoons Ni$

There is the deposition of 1 mole of Ni with 2 electrons transfer. The transfer of charge for 1 mole that is 58.7 grams Nickel is:

$\rm 58.7\;g=2\;\times\;96487\;C\\58.7\;g=192974\;C$

The mass of Ni to be deposited is 1.22 grams. The charge required is given as:

$\rm 58.7\;grams\;Ni=192974\;C\\\\1.22\;grams\;Ni=\dfrac{192974}{58.7}\;\times\;1.22\;C\\\\1.22\;grams\;Ni=4010.7\;C$

The current required to transfer 4010.7 C of charge in 1800 seconds is given as:

$\rm Charge=Current\;\times\;Time\\4010.7\;C=Current\;\times\;1800\;sec\\Current=2.23\;A$

Thus, the current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.

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1 year ago

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sammy [17]

Answer:

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Explanation:

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2 years ago

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