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Alika [10]
2 years ago
12

Clo3− draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. Show t

he formal charges of all nonhydrogen atoms.
Chemistry
1 answer:
Karo-lina-s [1.5K]2 years ago
3 0

The formal charges of all nonhydrogen atoms are -1.

Solution:-

<u>O 7-4 = 3 O Double bond on one H 5-4 = 1</u>

O-Cl-O 6-7 = -1x4 = -4 N 5-4=1 H-N-H 1-1=0

O 3-4= -1 O O 6-7 = -1(2)=-2 H 1-0=+1

<u>6-6 = 0 1-2 = -1</u>

It will percentage its last valence electron thru a single bond to the terminal oxygen atom. This is in agreement with carbon and hydrogen atoms that each need to form 4 and 1 covalent bonds respectively. because the terminal oxygen atom best has a single covalent bond, it'll have a proper rate of -1.

According to the lewis structure of SO2, The critical atom is sulfur and it is bonded with 2 oxygen atoms thru a double bond. each oxygen atom acquires 2 lone pairs of electrons and the primary sulfur atom has 1 lone pair of electrons.

Learn more about Nonhydrogen atoms here:-brainly.com/question/2822744

#SPJ4

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PLEASE PLEASE HELP ME!! I WILL BRAINLIST YOU!! A 28.0 g sample of N2 is in a rigid 4.50 L container at 32 °C. Calculate the pres
chubhunter [2.5K]

Answer:

P=4184.36 torr

Explanation:

For this problem we can use the idea gas law,

PV=nRT

where P is pressure, V is volume, n is moles of substance, R is the constant, and T is temperature, We will need to manipulate it and a couple values so that we can get our answer in torr. To do this, let's rearrange the equation to solve for P.

P=\frac{nRT}{V}

Next, let's convert T (32) to kelvin. To do this, add 273 to the value.

32+273=305

Next, let's convert 28g of N2 to moles of N2. To do this, divide 28 by the molar mass of N2 (28.02)

\frac{28.0}{28.01} \\=.99 moles of N2

Next, we need to find out what value of R we need to use. Because you want your answer in torr, we will need to use the value of

R=62.36\frac{torr}{mol*K}

Now that we have all of our values, let's plug them into the equation (I'll be excluding units for simplicity but they cancel out to leave units of torr in the answer)

P=\frac{(.99)(62.36)(305)}{4.50}\\P=4184.36

P=4184.36 torr

<em>Very briefly</em>, I don't know what your periodic table looks like, but mine has nitrogen's molar mass as 14.01. If you have a different mass of nitrogen, this pretty drastically impacts the value. For example, if your nitrogen's molar mass was rounded to 14.0 (making N2 28g) then it would be one mole instead of .99 moles, raising the answer to 4228.70 torr. If you have any different values just plug them in in their proper spots. A similar concept applies to the Kelvin conversion.

6 0
3 years ago
The end of the iron fire poker that you are holding gets warm even though it is not directly in the fire. The motion of the iron
AlladinOne [14]
I believe the statement is true. The heat transfer involved here is called conduction. It is one type of heat transfer where it caused by the collisions of the particles in a certain body. As the you add heat to the object, the kinetic energy of the molecules increases therefore more collisions could happen which would mean energy is dissipated or transferred from molecule to molecule.<span />
8 0
3 years ago
Read 2 more answers
For the reaction represented by the equation 2KClO3 → 2KCl + 3O2, how many grams of potassium chlorate are required to produce 1
Vikentia [17]

 The grams  of potassium chlorate  that are required  to produce 160 g of oxygen  is   408.29  grams

 

<u><em>calculation</em></u>

 2 KClO₃→  2 KCl  + 3O₂

Step 1:  find the  moles of  O₂

moles  =  mass÷  molar mass

from periodic table  the  molar mass of O₂  = 16 x2 = 32 g/mol

moles  = 160 g÷ 32  g/mol =  5 moles

Step2 : use the  mole   ratio to determine the  moles of KClO₃

from equation given KClO₃ : O₂  is 2:3

therefore the v moles of KClO₃  =  5 moles x 2/3 = 3.333  moles


Step 3:  find the mass  of KClO₃

mass= moles x molar mass

from periodic table  the molar mass of KClO₃

= 39 + 35.5 + (16 x3) =122.5 g/mol


mass  = 3.333 moles x 122.5 g/mol =408.29 grams

7 0
3 years ago
What would be the density if a nugget of gold’s mass of 965g and a volume of 50cm
olchik [2.2K]

p = 19.3 g/cm3


V√3=3.6840315cm :))

3 0
4 years ago
Read 2 more answers
Why is one able to walk on red-hot coals without getting one’s feet burned?
Hunter-Best [27]
Before the person walks through burning coal, the person will make sure their feet are very wet. When they start walking on the coal, the moisture will evaporate and form a protective gas layer underneath the person's feet.

You can see examples of this if you happen to drip some water on a hot stove or any hot surface. The water will easily glide around on top of a newly formed layer of air underneath it, like air hockey pucks on an air hockey table.

3 0
3 years ago
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