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Setler79 [48]
3 years ago
15

Help pleaaase!!

Physics
2 answers:
Agata [3.3K]3 years ago
8 0

Answer:

2.5m/s^{2}

Explanation:

Since the distance ,s = 500m

Initial velocity, u = 0m/s

Final velocity, v = 50m/s

We can one of the kinematics equations to find the acceleration.

v^{2} =u^{2} +2as\\50^{2} =0^{2} + 2a(500)\\2500 = 0 + 1000a\\1000a = 2500\\a = \frac{2500}{1000} \\= 2.5m/s^{2}

White raven [17]3 years ago
6 0

Answer:

S=D÷T

Explanation:

50=0.5÷T

T= 100

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5 0
4 years ago
Two 4.0 kg masses are 1.0 m apart on a frictionless table. Each has 1.0 μC of charge.What is the magnitude of the electric force
xeze [42]

Coulomb's law:

  Force = (<span>8.99×10⁹ N m² / C²<span>) · (charge₁) · (charge₂) / distance²

            = (</span></span><span>8.99×10⁹ N m² / C²<span>) (1 x 10⁻⁶ C) (1 x 10⁻⁶ C)  / (1.0 m)²

            = (8.99×10⁹ x 1×10⁻¹² / 1.0)  N

            =      8.99×10⁻³  N

            =        0.00899 N repelling.

Notice that there's a lot of information in the question that you don't need.
It's only there to distract you, confuse you, and see whether you know
what to ignore.

-- '4.0 kg masses';  don't need it. 
   Mass has no effect on the electric force between them.

-- 'frictionless table';  don't need it.
   Friction has no effect on the force between them,
only on how they move in response to the force.
</span></span>
7 0
3 years ago
Sally Sizzle builds a circuit by connecting three resistors in parallel with a 9V battery. The current in this circuit is 3.6 am
Andru [333]

Then answer is C 9 ohms

7 0
3 years ago
Read 2 more answers
An RLRL circuit with with a 1212-ΩΩ resistor and a 0.06−H0.06−H inductor carries a current of 1A1A at t=0t=0, at which time a vo
tankabanditka [31]

Answer:

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Explanation:

Resistance, R = 12 ohm

Inductance, L = 0.06 H

E (t) = 12 cos (120 t)

Compare with the standard equation,

E=E_{0}cos (2\pi ft)

2\pi ft = 120 t \\\\\\w = 2\pi f = 120 rad/s

So, the inductive reactance is

XL = w L = 120 x 0.06 = 7.2 ohm

The impedance of the circuit is

Z =\sqrt{12^2+7.2^2}\\\\Z = 14 ohm

The current leads  by 90degree so the equation of current is

I=\frac{Eo}{Z} cos \left (120 t + \frac{\pi}{2}  \right )\\\\I=\frac{12}{14} cos \left (120 t + \frac{\pi}{2}  \right )\\\\I=0.86 cos \left (120 t + \frac{\pi}{2}  \right )

4 0
3 years ago
In a game of basketball, a forward makes a bounce pass to the center. The ball is thrown with an initial speed of 4.8 m/s at an
tensa zangetsu [6.8K]
The equation to be used here is the trajectory of a projectile as written below:

y = xtanθ +/- gx²/2v²(cosθ)²
where
y is the vertical distance
x is the horizontal distance
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g is 9.81 m/s²
v is the initial velcity

Since the angle is below horizontal, let's use the minus equation. Substituting the values:

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5 0
4 years ago
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