Answer:
D. when each chromosome is duplicated
Answer:
B. is not manipulated and used for comparison
Explanation:A control group is merely a group placed on an experiment for comparing with the experimental group. The control group will receive no treatment and serves as a reference to measure the reactions of the subjects present in the group being tested.
The use of a control group is necessary for an experiment since the experiment has variables being tested and some other factor may arise in the carrying out of the experiment, that previously was not taken into account. It allows then to eliminate also non-essential variables.
Then researchers can make sure the hypothesis, remaining all variables the same for the tested groups will enable to measure the independent variable and see if this variable is to be held accountable for the results as the outcome of the research.
Answer:
Like questions 16-20? there aren't any questions to be answered.
Explanation:
Please attach something to this question.
Answer:
The correct answer is "selection favors multiple distinct trait values, and similar individuals tend to mate with each other".
Explanation:
A population with a bimodal distribution are groups of organisms with two major traits or "modes", with practically equal amounts of individuals with these two modes. This type of distributions indicate that the population is not homogenous and that more than one trait is favored in the given circumstances. A bimodal distribution is most likely to evolve when selection favors multiple distinct trait values, and similar individuals tend to mate with each other. In this case natural selection favors more than one value, and due to the individuals with one value tend to mate to each other, only two major traits are favored in the population.
I think the correct answer from the choices listed above is option D. Human height is determined by several genes located on different chromosomes which is an example of a polygenic trait. These traits are being controlled by more than one gene. Hope this answers the question.
