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2 years ago

How many solutions exist for the system of equations graphed below?

Mathematics

2 answers:

Zinaida [17]2 years ago

6 0

Answer:

one

Step-by-step explanation:

When a system of equations is graphed, the solution is the coordinate that is plotted at the intersection of the two lines.

If the two lines cross once, there is only one solution.

If the two lines are on top of each other then there are infinitely many solutions.

If the two lines are parallel ( and never touch ) then there are no solutions

By looking at the graph we notice the two lines intersect once. So we can conclude that there is only one solution.

Andreas93 [3]2 years ago

5 0

Answer: b) one

Detailed Explanation:

For the graph of a system of linear equations :-

• If the lines are parallel, then the pair of equations has no solution
• If the lines are coincident, then the pair of equations has infinite solutions
• If the lines are intersecting, then the pair of equations have one solution.

In this graph, the lines formed by the equations are intersecting at a point. Hence it has a unique solution.

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Relations and Functions, please help with these 3 questions asap. I will give brainliest! Only answer if you know how to do this

gladu [14]

<h2> Question # 1</h2>

Part A) Is the relation a function? Explain.

A function relates each element of a set with exactly one element of another set.

Important things for a relationship to be a function:

Every element in X is related to some element in Y.

A function cannot have one-to-many relationship.

A function must contain single valued, means it is not having one-to-many relation

Considering the points on coordinate plane

(-4, 2), (-3, 0), (-2, -1), (0, 2), (2, -3), (3, 3)

If we carefully observe, we determine that relation

relates each element of a set with exactly one element of another set

is single-valued, means It is not giving back 2 or more results for the same input. In other words, it is not having one-to-many relation.

It is in fact, having many to one. For example, the pairs (0, 2) and (-4, 2) is having many- to-one relationship.

So, from the above observation, it is clear that the relationship is a function.

Part B) What is the domain of the relation?

Considering the points on coordinate plane

(-4, 2)

(-3, 0)

(-2, -1)

(0, 2)

(2, -3)

(3, 3)

Also we know that domain of the relation is the set of all the x-values of an ordered pairs.

So, the domain of the relation: {-4, -3, -2, 0, 2, 3}

Part C) What is the range of the relation?

Considering the points on coordinate plane

(-4, 2)

(-3, 0)

(-2, -1)

(0, 2)

(2, -3)

(3, 3)

As we know that the range of a relationship is the set of all the y-values of an ordered pair.

So, the range of the relationship will be: { -3, -1, 0, 2, 3}

<em>Note:</em>

The duplicated entries in the domain and range are written only once.
Also, the domain and range can be written in ascending order.

Part D) What is the value of y when x = 2? Explain

Considering the points on coordinate plane

(-4, 2)

(-3, 0)

(-2, -1)

(0, 2)

(2, -3)

(3, 3)

From the given points on the coordinate plane, it is clear that when the value of x = 2, then the value of y = -3

Therefore, the value of y is -2 when x = 2

<h2> Question # 2</h2>

Considering the points on coordinate plane

(-4, -1), (-2, 1), (0, -3), (2, 3), (4, -2)

If we bring a point, let say (2, 4), and graphed on the coordinate system, then the relation will no longer be function.

The reason is that the induction of the point (2, 4) would violate the definition of a relation to be a function.

Observe that (2, 4) and (2, 3) will make the relation having one-to-many relationship as (2, 4) and (2, 3) is giving 2 outputs i.e. y = 4, and y = 3 for a single input i.e. x = 2.

Therefore, the induction of the point (2, 4), when graphed, makes the relation not a function.

<h2> Question # 3</h2>

Part A)

$f\left(x\right)\:=\:|x\:-\:3|\:-\:2$ ; $x = -5$

The attached figure a shows the graph for the function

$f\left(x\right)\:=\:|x\:-\:3|\:-\:2$

In the attached figure a, the graph represents an absolute value relationship as the absolute value of a number is never negative.

Evaluate the function for x = -5

$f\left(x\right)\:=\:|x\:-\:3|\:-\:2$

$|\left-5\right\:-\:3|\:-\:2....[A]$

Solving

$\left|-5-3\right|$

$\mathrm{Subtract\:the\:numbers:}\:-5-3=-8$

$=\left|-8\right|$

$\mathrm{Apply\:absolute\:rule}:\quad \left|-a\right|=a$

$\left|-8\right|=8$

So,

$\left|-5-3\right|=8$

Equation [A] becomes

$\:|-5\:-\:3|\:-\:2\:=8\:-\:2\:$ ∵ $\left|-5-3\right|=8$

$=6$

Therefore,

the value of $f\left(x\right)\:=\:|x\:-\:3|\:-\:2$ at $x = -5$ will be 6.

i.e. $f(x)=6$

<h2 />

Part B)

$g\left(x\right)=1.5x;\:x=0.2$

The attached figure b shows the graph for the function

$g\left(x\right)=1.5x$

In the attached figure b, the graph shows that the function represents a linear relationship as the graph is a straight line.

Evaluate the function for x = 0.2

$g\left(x\right)=1.5x$

Putting x = 0.2

$g\left(x\right)=1.5\left(0.2\right)$

$1.5\left(0.2\right)=0.3$

$g\left(x\right)=0.3$

So,

the value of $g\left(x\right)=1.5x$ at $x = 0.2$ will be 0.3.

i.e. $g\left(x\right)=0.3$

Part C)

$p\left(x\right)\:=\:|7\:-\:2x|;\:x\:=\:-3$

As the absolute value of a number will be never negative.

The attached figure c shows the graph for the function

$p\left(x\right)\:=\:|7\:-\:2x|$

In the attached figure c, the graph represents an absolute value relationship as the absolute value of a number is never negative.

Evaluate the function for x = -3

$p\left(x\right)\:=\:|7\:-\:2x|$

Solving

$\left|7-2x\right|$

$\left|7-2\left(-3\right)\right|$

$=\left|7+6\right|$

$=\left|13\right|$

$\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0$

$=13$

So,

$\left|7-2x\right|=13$

So,

the value of $p\left(x\right)\:=\:|7\:-\:2x|$ at $x = -3$ will be 13.

i.e $p\left(x\right)\:=13$

Keywords: function, relation

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4 years ago

If the radius of circle is r cm.write domn the measurement of area of that circle

jeka94

3.14^2 ?.?.?.?.??..?.?.?

8 0

3 years ago

Help please! This is timed! 50 points

kiruha [24]

Answer:

24.96%

Step-by-step explanation:

HOPE I WAS FAST ENOUGH

7 0

4 years ago

Read 2 more answers

The temperature of a liquid in an experiment changes by -10.4F from the beginning of the experiment to the first check. After ma

marta [7]

Answer:

63.5F

Step-by-step explanation:

Let x represent the temperature at the start of the experiment. Then the temperature at first check is (x -10.4F). The temperature at the second check is 1/3 that value, and is said to be 17.7F. This lets us write the equation ...

1/3(x -10.4F) = 17.7F

Multiplying by 3 gives ...

x -10.4F = 53.1F

x = 63.5F . . . . . . add 10.4F

The initial temperature of the liquid was 63.5F.

_____

<em>Additional comment</em>

Temperature is measured on an "interval scale." On such a scale, the value 0 is located arbitrarily. Concepts such as "1/3 of the temperature" have no meaning on such a scale. Here, we have to ignore that fact and assume the problem is about the numbers, not about any real temperature relationship in thermodynamic terms.

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3 years ago

Question 4

Maksim231197 [3]

Answer:

Negative slope Hopefully

Step-by-step explanation:

Slope formula : (5 - (-1)) / (-4 - 1)

6/-5 = a negative slope

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4 years ago