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aleksandrvk [35]
3 years ago
13

As every Girl Scout knows, statistics teachers seriously love Girl Scout Cookies. The number of boxes of GS cookies statistics t

eachers order, like all important decisions made by statistics teachers, is determined by independent rolls of a 4-sided fair die. If a one appears, 6 boxes are ordered; if any other number appears, 2 boxes are ordered.
a) What is the probability that a statistics teacher places an order for 2 boxes of Girl Scout cookies?
b) What is the probability that with two independently chosen statistics teachers will each order 6 boxes each?
c) What is the probability that for two independently chosen statistics teachers the first will order 6 boxes and the second will order 2 boxes?
d) What is the probability that for two independently chosen statistics teachers exactly one will order 6 boxes?
Mathematics
1 answer:
Alexandra [31]3 years ago
4 0

Answer:

a) 0.75

b) 0.0625

c) 0.1875

d) 0.375

Step-by-step explanation:

Let's start by first finding the probability a teacher orders 6 boxes. Since it is a four sided dice, the probability of getting a 1 is going to be 0.25.

Similarly, for any other number on the dice, the teacher orders 2 boxes. We can think of this as NOT rolling a 1. Using our previous answer, this comes out to be: 1 - 0.25 = 0.75

It should be remembered in the following answers that teachers ordering 6 or 2 boxes are not influenced by the results of other teachers. These are statistically independent events.

a) As given above, this probability is 0.75

b) The probability that both teachers order 6 boxes will be their individual probabilities multiplied. This comes out to be: 0.25 x 0.25 = 0.0625

c) Like in part (b), this is both of their probabilities multiplied:

   0.25 x 0.75 = 0.1875

d) This is nearly the same as part (c), but with a little twist. The order matters. There are two scenarios:

  1.   First teacher gets 6 boxes, and the second gets 2.
  2.   First teacher gets 2 boxes, and the second gets 2.

Both of these events have a probability of 0.1875, as shown in (c). To get the total probability of this event happening, we must add these together:

0.1875 + 0.1875 = 0.375

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kupik [55]

Answer:

d_{AB}\ne d_{JK}

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d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

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Finding the length of AB using the formula

d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

        =\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}

         =\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}

         =\sqrt{6^2+1}

         =\sqrt{36+1}

        =\sqrt{37}

d_{AB}\:=\sqrt{37}

d_{AB}=6.08 units        

Given the vertices of the segment JK

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From the graph, it is clear that the length of JK = 5 units

so

d_{JK}=5 units

Given the vertices of the segment GH

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  • H(-2, -2)

Finding the length of GH using the formula

d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

         =\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}

          =\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}

          =\sqrt{3^2+0}

           =\sqrt{3^2}

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

d_{GH}\:=\:3 units

Thus, from the calculations, it is clear that:

d_{AB}=6.08  

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d_{GH}\:=\:3

Thus,

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

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Step-by-step explanation:

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