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lutik1710 [3]
3 years ago
9

The function f(x) = x2. The graph of g(x) is f(x) translated to the left 6 units and down 5 units. What is the function rule for

g(x)?
Question 18 options:

g(x) = (x + 6)2 - 5

g(x) = (x - 5)2 + 6

g(x) = (x + 5)2 - 6

g(x) = (x - 6)2 + 5
Mathematics
1 answer:
Y_Kistochka [10]3 years ago
6 0

Answer:

g(x) = (x + 6)^2 - 5

Step-by-step explanation:

To translate f(x) to the left by 6 units, replace x with x+6.

To translate f(x) down 5 units, replace f(x) with f(x)-5.

Together, these replacements give you ...

... g(x) = f(x+6) -5

... g(x) = (x +6)^2 -5

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What would you see at the wedding of Betty Crocker and the pillsbury dough boy
Mrrafil [7]
Cake
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Sugar
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3 0
3 years ago
Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous plan
vladimir1956 [14]

Answer:

its 450 k

Step-by-step explanation:

It is given that the temperature of the gaseous planet is linearly related with height of the atmosphere. we can write this in the mathematical equation:

y = m x +c

where y is the temperature values, x is height, m is the slope and c is the y-intercept. we have been given two sets of value in the image, using which we can find the value of slope in y-intercept.

at x = 18.40 km, y = 147.54 K

⇒147.54 = 18.40 m + c      

⇒c = 147.54 - 18.40 m  ..(1)

at x =78.11 km, y = 567.00 K

⇒567.00 =78.11 m + c       ..(2)

Put equation 1 in 2 and solve:

⇒567.00 =78.11 m + 147.54 - 18.40 m

⇒419.46 = 59.71 m

⇒ m =419.46 ÷59.71 = 7.025 K/km

c = 147.54 - 18.40 × 7.025 = 18.28 K

At height, x = 61.5 km the approximate temperature is :

y = 7.025 K/km ×  61.5 km + 18.28 K = 450.3 K

Thus, the approximate temperature at altitude 61.5 km is 450 K.

7 0
3 years ago
Help me pleaseeee I need it
Marta_Voda [28]
4(2x5 + 3) - 4(2) + 2(5).

4(13) - 18.

52-18 = 34.
4 0
2 years ago
Read 2 more answers
Please help me..........<br><br>only 32,and 33​
kupik [55]

Answer:

Step-by-step explanation:

32

Step 1 : Draw PQ = 6cm

Step 2 : Construct 60 degree at Q. [Given PQR = 60=> Q = 60 ]

Step 3 : Take 5 cm on compass and mark 5cm on the 60 degree

            line constructed at Q.

Step 4 : The arc of 5cm and 60 degree line  meets is the point R.

             [Given QR = 5cm ]

Step 5 : Given PQ || SR so construct a 120° at R ,

             because ∠PQR and ∠QRS are supplementary angle.

            [ ∠PQR + ∠QRS = 60 + 120 = 180° ]

Step 6 : At P , take 6.5 cm on compass and mark on the line drawn in

             Step 5, to get S. [ Given PS = 6.5 ]

           

33

Given adjacent sides : 4.8 and 4.2

And it is a rectangle.

Step 1 : construct AB = 4.8 cm

Step 2 :At A and B construct 90 degree

Step 3: On the compass take 4.2cm and mark on the 90degree lines

          from A and B.

Step 4 : Mark that as C and D respectively.

Step 5 : Join CD

8 0
3 years ago
Pls help! will mark branliest!!! :)
Ket [755]

The area of the house is the amount of space on the house.

  • The length of the addition is x + 20
  • The area of the original house is x^2 + 30x + 200

<h3>The length of the addition</h3>

The area of the addition is given as:

Area = x^2 + 10x - 200

Expand

Area = x^2 + 20x - 10x - 200

Factorize

Area = x(x + 20) - 10(x + 20)

Factor out x + 20

Area = (x -10)(x + 20)

The width of the addition is x - 10.

Hence, the length of the addition is x + 20

<h3>The area of the original house</h3>

The dimension of the original house is

x + 20 by x + 10

So, the area is:

Area =(x + 20)(x + 10)

Expand

Area =x^2 + 20x + 10x + 200

This gives

Area =x^2 + 30x + 200

Hence, the area of the original house is x^2 + 30x + 200

Read more about areas at:

brainly.com/question/24487155

8 0
2 years ago
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