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3 years ago

HELP PLEASE DJEJJDJDBFHERHDHKJE

Mathematics

1 answer:

Serhud [2]3 years ago

6 0

Solution:

Total number of students=273

Let x students choose Tiger. Then we can write

Number of students who choose Bulldog $=4x$

Number of students who choose Lion $=2x$

So we can write

$x+2x+4x=273\\
\\
7x=273\\
\\
x=39\\$

Hence a total of 39*2=78 student choose Tiger.

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If the Revenue for the week is $2000, and labor cost consists of two workers earning $8 per hour who work 40 hours each, what is

slega [8]

So,

All you have to do is find the total labor cost and put it over the revenue.

We have two workers each earning $8/hr. (lousy), and they work 40 hrs./week.

2 * $8 = $16/hr.

$16/hr. * 40 hrs. = $640

$\frac{640}{2000}$

Cross out zeros.
$\frac{64}{200}$

Simplify.
$\frac{2^6}{2^35^2}$
$\frac{2^3}{5^2}$
$\frac{8}{25}$

Convert the denominator to 100.
$\frac{8}{25} * \frac{4}{4} = \frac{32}{100}$
$\frac{32}{100}$
=
32%

The labor cost is 32% of the revenue.

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3 years ago

During the grand opening of an electronics store, any customer has an 11% chance of winning a free laptop. What is the chance th

timama [110]

To get the answer you would subtract 11% from 100%, getting the answer 89%.

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3 years ago

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Which ratio best defines experimental probability?

Lostsunrise [7]

B. Total number of times the activity is performed: Number of times an event occurs

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2 years ago

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A used book store also started selling used CDs and videos. In the first week, the store sold 40 used CDs and videos, at 4.00 pe

masha68 [24]

Answer:

30 CDs and 10 Videos were sold.

Step-by-step explanation:

Given that a used book store also started selling used CDs and videos. In the first week, the store sold 40 used CDs and videos, at 4.00 per CD and 6.00 per video.

The sales for both CDs and videos totaled to 180.00.

Let CDs be x and Videos be y

Then we have x+y =3040

and 4x+6y = 180

Two simultaneous equations in two variables and can be solved by elimination method

multiply I equation by 4 and subtract from II.

2y = 20

y =10

x = 30

30 CDs and 10 Videos were sold.

4 0

3 years ago

Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x

BaLLatris [955]

Answer:

The area of the region is 25,351 $units^2$ .

Step-by-step explanation:

The Fundamental Theorem of Calculus: if $f$ is a continuous function on $[a,b]$ , then

$\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}$

where $F$ is an antiderivative of $f$ .

A function $F$ is an antiderivative of the function $f$ if

$F^{'}(x)=f(x)$

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function $x^5 + 8x^4 + 2x^2 + 5x + 15$ and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

$\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx$

$\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2$

3 0

3 years ago