Given that the perimeter of rhombus ABCD is 20 cm, the length of the sides will be:
length=20/4=5 cm
the ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that:
AC=4x and BD=3x
using Pythagorean theorem, the length of one side of the rhombus will be:
c^2=a^2+b^2
substituting our values we get:
5²=(2x)²+(1.5x)²
25=4x²+2.25x²
25=6.25x²
x²=4
x=2
hence the length of the diagonals will be:
AC=4x=4×2=8 cm
BD=3x=3×2=6 cm
Hence the area of the rhombus wll be:
Area=1/2(AC×BD)
=1/2×8×6
=24 cm²
Answer:
-3 < x
Step-by-step explanation:
15 > -5x
Divide each side by -5, remembering to flip the inequality since we are dividing by a negative
15/-5 < -5x/-5
-3 < x
Answer:
The answer is x=−1247
Step-by-step explanation:
Let's solve your equation step-by-step.
1+39(12−44)=x
Step 1: Simplify both sides of the equation.
1+39(12−44)=x
1+−1248=x
(1+−1248)=x(Combine Like Terms)
−1247=x
−1247=x
Step 2: Flip the equation.
Answer: x=−1247
Thirty-two thousand six hundred fifty-one
