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-BARSIC- [3]
2 years ago
14

Which quadratic function is represented by the graph?

Mathematics
1 answer:
Vesnalui [34]2 years ago
3 0

The equation of the quadratic function will be y = 5(x – 7)(x – 5). Then the correct option is B.

<h3>What is a quadratic equation?</h3>

The quadratic equation is given as ax² + bx + c = 0. Then the degree of the equation will be 2. Then we have

The quadratic function is represented by the graph.

Then the equation of the quadratic function will be

The graph is passing through (7, 0) and (5, 0). Then the equation of the function will be

y = a(x – 7)(x – 5)

Then the vertex of the graph is at (6, -5). Then we have

-5 = a(6 – 7)(6 – 5)

-5 = -a

a = 5

Then the equation will be

y = 5(x – 7)(x – 5)

Then the correct option is B.

More about the quadratic equation link is given below.

brainly.com/question/2263981

#SPJ1

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S 61 – 9u = 10
Shkiper50 [21]

Answer:

Step-by-step explanation:

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4 0
3 years ago
−1/3−(−1/2)
Radda [10]

Hi ;-)

-\frac{1}{3}-(-\frac{1}{2})=-\frac{1}{3}+\frac{1}{2}=-\frac{2}{6}+\frac{3}{6}=\frac{3}{6}-\frac{2}{6}=\frac{1}{6}\\\\3\frac{1}{3}-5=-(5-3\frac{1}{3})=-(4\frac{3}{3}-3\frac{1}{3})=-1\frac{2}{3}\\\\-1\frac{4}{5}-(-2\frac{7}{8})=-1\frac{4}{5}+2\frac{7}{8}=-1\frac{32}{40}+2\frac{35}{40}=2\frac{35}{40}-1\frac{32}{40}=1\frac{3}{40}\\\\-3\frac{3}{8}-\frac{7}{8}=-(3\frac{3}{8}+\frac{7}{8})=-3\frac{10}{8}=-3\frac{5}{4}=-4\frac{1}{4}\\\\4\frac{3}{4}-(-1\frac{1}{12})=4\frac{9}{12}+1\frac{1}{12}=5\frac{10}{12}

6 0
3 years ago
3. If mZEFH = (5x + 1), mZHFG = 62°, and<br> mZEFG = (18x + 11), find each measure.
arsen [322]

Answer/Step-by-step explanation:

Given:

m<EFH = (5x + 1)°

m<HFG = 62°

m<EFG = (18x + 11)°

Required:

1. Value of x

2. m<EFH

3. m<EFG

SOLUTION:

1. Value of x

m<EFH + m<HFG = m<EFG (angle addition postulate)

(5x + 1) + 62 = (18x + 11)

Solve for x using this equation

5x + 1 + 62 = 18x + 11

5x + 63 = 18x + 11

Subtract 18x from both sides

5x + 63 - 18x = 18x + 11 - 18x

-13x + 63 = 11

Subtract 63 from both sides

-13x + 63 - 63 = 11 - 63

-13x = -52

Divide both sides by -13

-13x/-13 = -52/-13

x = 4

2. m<EFH = 5x + 1

Plug in the value of x

m<EFH = 5(4) + 1 = 20 + 1 = 21°

3. m<EFG = 18x + 11

m<EFG = 18(4) + 11 = 72 + 11 = 83°

8 0
4 years ago
PLZ HELP ME!!! ILL MARK BRAINLIEST!!!!!
natka813 [3]

Answer:

well algebra is basically about variables.

This is because you're assigning an equation or a number to a letter.

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7 0
3 years ago
Find the later area of the figure
o-na [289]

Answer:

\large\boxed{60\pi\ sq.in.}

Step-by-step explanation:

The formula of a lateral area of a cone:

L.A.=\pi rl

r - radius

l - lateral height

We have the radius r = 6in and the height H = 8in.

Use the Pythagorean theorem to calculate the lateral height:

l^2=6^2+8^2\\\\l^2=36+64\\\\l^2=100\to l=\sqrt{100}\\\\l=10\ in

Substitute:

L.A.=\pi(6)(10)=80\pi\ in^2

3 0
3 years ago
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