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2 years ago

Which quadratic function is represented by the graph?

Mathematics

1 answer:

Vesnalui [34]2 years ago

3 0

The equation of the quadratic function will be y = 5(x – 7)(x – 5). Then the correct option is B.

<h3>What is a quadratic equation?</h3>

The quadratic equation is given as ax² + bx + c = 0. Then the degree of the equation will be 2. Then we have

The quadratic function is represented by the graph.

Then the equation of the quadratic function will be

The graph is passing through (7, 0) and (5, 0). Then the equation of the function will be

y = a(x – 7)(x – 5)

Then the vertex of the graph is at (6, -5). Then we have

-5 = a(6 – 7)(6 – 5)

-5 = -a

a = 5

Then the equation will be

y = 5(x – 7)(x – 5)

Then the correct option is B.

More about the quadratic equation link is given below.

brainly.com/question/2263981

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Make a the subject of a2+b2=c2

wel

Answer:

$a=\sqrt{c^2-b^2$

⇒ $a=\sqrt{(c+b)(c-b)}$ [Factorized form]

Step-by-step explanation:

Given expression:

$a^2+b^2=c^2$

We need to make $a$ the subject.

In order to do that we need to solve the expression for $a$ in terms of $b$ and $c$

We have,

$a^2+b^2=c^2$

Subtracting both sides by $b^2$

$a^2+b^2-b^2=c^2-b^2$

$a^2=c^2-b^2$

Taking square root both sides in order to remove square of $a$

$\sqrt{a^2}=\sqrt{c^2-b^2}$

$a=\sqrt{c^2-b^2$

The difference of squares can be factorized and written as:

$a=\sqrt{(c+b)(c-b)}$ [difference of squares $x^2-y^2=(x+y)(x-y)$ ]

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3 years ago

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almond37 [142]

Interest depends a lot on the compounding period.
Since the period is exactly 4 months, we assume
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3 years ago

Write an equation in standard form for the line that passes<br> through (-1,-2) and (3.0)

Agata [3.3K]

Answer:

y+2=1/2(x+1)

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(0-(-2))/(3-(-1))

m=(0+2)/(3+1)

m=2/4

m=1/2

y-y1=m(x-x1)

y-(-2)=1/2(x-(-1))

y+2=1/2(x+1)

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3 years ago

Whats the square root of 34 in simplest form?

natali 33 [55]

That is in its simpist form already, trick question.

7 0

3 years ago

What are the solutions to this problem? (use the quadratic formula and i)<br><br> -2x^2+5x-11=0

Sever21 [200]

Step-by-step explanation:

The quadratic formula is:

$x = \frac{-b \pm\sqrt{b^2-4ac} }{2a}\\$

A, in this case, is -2.

B is 5

C is -11

x = $\frac{-5 \pm\sqrt{5^2-4(-2)(-11)} }{2(-2)}$

x = $\frac{-5\pm\sqrt{25 -88} }{-4}\\$

x = $\frac{-5\pm\sqrt{-63}}{-4}$

x = $\frac{-5+i\sqrt{63} }{-4}$ and $\frac{-5-i\sqrt{63} }{-4}$

We can break up the fraction to make it easier on our eyes

x = $\frac{5}{4}\pm\frac{i\sqrt{63} }{4}$

$\frac{\sqrt{63} }{4}$ ≈1.9843

x = $1.25 + 1.9843i\\1.25 - 1.9843i$

7 0

3 years ago

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