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2 years ago

32. Which graph represents yas a function of x?

Mathematics

1 answer:

Lera25 [3.4K]2 years ago

6 0

Answer:

second one

Step-by-step explanation:

i am pretty sure

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A radioactive substance decays exponentially: The mass at time t is m(t) = m(0)e^kt, where m(0) is the initial mass and k is a n

forsale [732]

Answer:

mean life = 8264.5 s

Step-by-step explanation:

k = - 0.000121

The relation is given by

$m = mo e^{kt}$

Now, the mean life is the life time for which the sample retains.

The mean life is the reciprocal of the decay constant.

The relation between the mean life and the decay constant is

$\tau =\frac{1}{k}\\\\\tau = \frac{1}{0.000121} = 8264.5 seconds$

5 0

3 years ago

Twenty percent of drivers driving between 10 pm and 3 am are drunken drivers. In a random sample of 12 drivers driving between 1

Lesechka [4]

Answer:

(a) 0.28347

(b) 0.36909

(d) 0.9806

Step-by-step explanation:

Given information:

n=12

p = 20% = 0.2

q = 1-p = 1-0.2 = 0.8

Binomial formula:

$P(x=r)=^nC_rp^rq^{n-r}$

(a) Exactly two will be drunken drivers.

$P(x=2)=^{12}C_{2}(0.2)^{2}(0.8)^{12-2}$

$P(x=2)=66(0.2)^{2}(0.8)^{10}$

$P(x=2)=\approx 0.28347$

Therefore, the probability that exactly two will be drunken drivers is 0.28347.

(b)Three or four will be drunken drivers.

$P(x=3\text{ or }x=4)=P(x=3)\cup P(x=4)$

$P(x=3\text{ or }x=4)=P(x=3)+P(x=4)$

Using binomial we get

$P(x=3\text{ or }x=4)=^{12}C_{3}(0.2)^{3}(0.8)^{12-3}+^{12}C_{4}(0.2)^{4}(0.8)^{12-4}$

$P(x=3\text{ or }x=4)=0.236223+0.132876$

$P(x=3\text{ or }x=4)\approx 0.369099$

Therefore, the probability that three or four will be drunken drivers is 0.3691.

(c)

At least 7 will be drunken drivers.

$P(x\geq 7)=1-P(x$

$P(x\leq 7)=1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)+P(x=6)]$

$P(x\leq 7)=1-[0.06872+0.20616+0.28347+0.23622+0.13288+0.05315+0.0155]$

$P(x\leq 7)=1-[0.9961]$

$P(x\leq 7)=0.0039$

Therefore, the probability of at least 7 will be drunken drivers is 0.0039.

(d) At most 5 will be drunken drivers.

$P(x\leq 5)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)$

$P(x\leq 5)=0.06872+0.20616+0.28347+0.23622+0.13288+0.05315$

$P(x\leq 5)=0.9806$

Therefore, the probability of at most 5 will be drunken drivers is 0.9806.

5 0

3 years ago

Does anyone know this?

Tresset [83]

<ABC would equal 106

seeing in triangle ABD angle A equals 67 you would multiply that by 2 and then subtract it from 180 to get 46, and then triangle DBC all the angles would equal 60. so then add 46 to 60 to get 106 the measure of <ABC

3 0

3 years ago

Nind reeds

Usimov [2.4K]

Answer:

42 gallons.

Step-by-step explanation:

count every inch *2 and calculate gallons

3 0

2 years ago

PLEASE HELP !! I'LL GIVE YOU BRAINLIEST !!

Marizza181 [45]

Sorry but, there’s nothing attached so I can not help you.

3 0

2 years ago

Read 2 more answers